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oksano4ka [1.4K]
3 years ago
15

An enclosed gas exerts a pressure P on the walls of a container. This pressure is directly proportional to the temperature T of

the gas, measured in Kelvin. If the pressure is 7 lb per square inch when the temperature is 420ºK, find the constant of variation.
Mathematics
2 answers:
zimovet [89]3 years ago
8 0

Keywords:

<em>Variation constant, directly proportional, temperature, pressure </em>

For this case, we must find the constant of variation, knowing that the pressure is directly proportional to the temperature, knowing the values of pressure and temperature. So, we have:

P = aK

Where "a" is the constant of variation or constant of proportionality

If P = 7 \frac {lb} {in ^ 2}\\T = 420K

Substituting:

7 \frac {lb} {in ^ 2} = a*420K

Clearing to:

a = \frac {7} {420} \frac {lb} {K * in ^ 2}, if we divide by 7 the numerator and denominator we have:

Thus, the constant of variation is given by:

a = \frac {1} {60} \frac {lb} {K * in ^ 2}

Answer:

The variation constant is given by: a = \frac {1} {60} \frac {lb} {K * in ^ 2}

tatyana61 [14]3 years ago
5 0
Don't know if i'm right but I got 1/60

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