All categories

3 years ago

Please answer fast Silakan

Mathematics

2 answers:

irina1246 [14]3 years ago

4 0

12 16/56 + 3 35/56 = 15 51/56

xeze [42]3 years ago

4 0

Answer:

$8\frac{37}{56}$

Step-by-step explanation:

$12\frac{2}{7} + 3\frac{5}{8} = \frac{86}{7} + \frac{29}{8} = \frac{688 - 203}{56} = \frac{485}{56} = 8\frac{37}{56}$

You might be interested in

What is the inverse of the function f(x) = x +3?

KatRina [158]

Next time please add answer choices

f(x) = y = x+3, Consider y=x+3. You just switch x and y:
so y= x+3, becomes x=y+3. Once done, you isolate y:
x=y+3 or y = x-3. This this the inverse function of f(x)

5 0

3 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

A football field is 1000 yards long.Each if the two end zones adds an extra 10 yards . The field is 160 feet wide . What is the

Kobotan [32]

Answer:

The area of the whole field is 54400yd^2

Step-by-step explanation:

says that I add 10 yards in each zone, that means that 10 yards is added twice at 1000 yards

1000yd + 2*10yd = 1020yd

we have to know that one yard equals 3 feet

so to have the length in feet we only multiply it by 3

1020 * 3 = 3060ft

Now that we know the length and width of the court, we can calculate the area by multiplying them

a = b * h

a = 3060ft * 160ft

a = 489600 ft^2

the result is in square feet

if we want it in square yards we just have to divide 2 times by 3

489600/(3*3) = 54400yd^2

7 0

3 years ago

Read 2 more answers

Sonya is 22 years younger than her mother. the sum of their age is 32. how old are they

Fantom [35]

Answer:

Sonya is ten her mother is 22

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the coefficient of X^2Y^2 in the expansion of (x+y)^4

nata0808 [166]

Answer:

Step-by-step explanation:

We want to expand this; (x + y)⁴

This can be written as;

(x + y)² × (x + y)²

This gives;

(x² + 2xy + y²) × (x² + 2xy + y²)

This gives;

x²(x² + 2xy + y²) + 2xy(x² + 2xy + y²) + y²(x² + 2xy + y²) = x⁴ + 2x³y + x²y² + 2x³y + 4x²y² + 2xy³ + x²y² + 2xy³ + y⁴

Simplifying gives;

x⁴ + 4x³y + 4xy³ + 6x²y² + y⁴

Thus, the coefficient of x²y² is 6

3 0

2 years ago