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andreev551 [17]
3 years ago
15

How to solve this...

20" id="TexFormula1" title=" \frac{5}{9} + \frac{4}{8} = " alt=" \frac{5}{9} + \frac{4}{8} = " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Monica [59]3 years ago
4 0

19

-----

18

or

1.0555555556

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Solve the right triangle below. Round sides to the nearest thousandth and angles to the nearest degree.
aalyn [17]

Answer:

Option 4, BC = 12.689, m∠A = 58°, and m∠C = 32°

Hope this helps!

4 0
3 years ago
What is 10/13 + 8/13 ?
ludmilkaskok [199]
18/13 or in simplified form, 1 and 5/13.
4 0
3 years ago
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Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
use a ratio box to solve this problem. There were 144 books about mammals in the library. If the ratio of books about mammals to
kherson [118]

Answer:

128

Step-by-step explanation:

8 0
2 years ago
Use the square root property of equality to solve (x  – 3)2 = –4. The solutions are a. -1 or 7 b. 1 or 5 c. 3+- 2i d. 3+-4i
makkiz [27]
The answer is C. 3+-2i

(x-3)(x-3)^{2} = -4

 \sqrt{(x-3)^2} = +- \sqrt{-4

x - 3 = i \sqrt{4} 

x - 3 = +-2i

x = 3 +-2i
6 0
3 years ago
Read 2 more answers
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