Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
First find the perimeter. Then take the depth of the pool and multiply it by the perimeter.
Hope this helps
3/4 times 1 1/2 = 1 1/8
Hope this helps!
Answer:
{-8, -7, 0, 6, 9}
Step-by-step explanation:
1. The range of a relation is the set of its possible output values, also known as the y-values of a function.
2. Let's find the y-coordinate of each point.
3. Now, let's order them (from least to greatest) to get the range.
- {-8, -7, 0, 6, 9}
Therefore, the range of this relation is {-8, -7, 0, 6, 9}.
Answer:
The discriminant is 49
Step-by-step explanation: