The horizontal distance between light house and boat is 1588.78 feet approximately.
The figure is given by,
Here, AB = height of the lighthouse bacon light above the water = 139 feet
Now angle ACB = 5 degree
Let the horizontal distance of light house from the boat = BC = x feet
So by trigonometric function we get,
tan 5 = AB/BC
tan 5 = 139/x
x = 139/tan 5 = 1588.78 (approximately)
Hence the horizontal distance between light house and boat is 1588.78 feet approximately.
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7x - 2y = -3
14x + y = 14
14x -14x + y = 14-14x
Y = 14 - 14x
7x -2y = -3
7x - 2(14 - 14x) = -3
7x -28 + 28x = -3
7x + 28x - 28 = -3
35x - 28 = -3
35x - 28 + 28 = -3 + 28
35x = 25
35x/35 = 25/35
X = 25/35 = 5/7.
Y = 14 - 14x
Y = 14 - 14(5/7)
Y = 14 - 10
Y = 4.
The solution P(5/7,4).
6. 5 shirts 20 minutes Multiply both by 3 to get to 60 minutes
15 shirts 60 minutes
15 shirts per hour
7. 250 miles + 50 miles = 300 miles
300 miles / 5 hours = 60 miles per hour
8. 360 pages / 12 hours = 30 pages per hour400 pages / 30 pages per hour = 13 1/3 hours
= 13 hours and 20 minutes
Area inside the semi-circle and outside the triangle is (91.125π - 120) in²
Solution:
Base of the triangle = 10 in
Height of the triangle = 24 in
Area of the triangle = 
Area of the triangle = 120 in²
Using Pythagoras theorem,
Taking square root on both sides, we get
Hypotenuse = 23 inch = diameter
Radius = 23 ÷ 2 = 11.5 in
Area of the semi-circle = 
Area of the semi-circle = 91.125π in²
Area of the shaded portion = (91.125π - 120) in²
Area inside the semi-circle and outside the triangle is (91.125π - 120) in².
