The measure of the side
is approximately 33 and the measure of angle
is approximately 12.321°.
<h3>How to find a missing angle in a triangle by law of sine and law of cosine</h3>
In this problem we must apply the law of cosine and the law of sine to determine the angle Y:
<h3>Law of cosine</h3>



<h3>Law of sine</h3>




The measure of the side
is approximately 33 and the measure of angle
is approximately 12.321°. 
To learn more on triangles, we kindly invite to check this verified question: brainly.com/question/25813512
I cant answer if there is no info
answer.
Answer:
x=2 and y=0 is the required result.
Step-by-step explanation:
We have been given system of equations:
5x+2y=105x+2y=10 (1)
And 3x+2y=63x+2y=6 (2)
We will use elimination method:
Multiply 1st equation by 3 and 2nd equation by 5 we get:
15x+6y=3015x+6y=30 (3)
15x+10y=3015x+10y=30 (4)
Now subtract (4) from (3) we get:
-4y=0−4y=0
y=0y=0
Now, put y=0 in (1) equation:
5x+2(0)=105x+2(0)=10
5x=105x=10
x=2x=2
Hence, x=2 and y=0
Answer:
2/5x = 3/20 or 2/5 *x = 3/20
Step-by-step explanation:
These are the same thing just different ways to write. The x represents the unknown number
For the one on the left they are corresponding and on the right they are vertical