Answer:
[ See the attached picture ]
The diagonals of a parallelogram bisect each other.
✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.
✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.
Proof :
♕ And we're done! Hurrayyy! ;)
# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P
☄ Hope I helped! ♡
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The answer is 16 because 8 goes into 24 3 times so 8 + 8 is 16
Answer:
32.1%
Did you type something in wrong?
Step-by-step explanation:
9+4+15=28 total balls
9=total red balls
total red balls/total balls= probability of pulling out one red ball
9/28
9÷28=32.1%