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3 years ago

What is the x-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:5?

Mathematics

2 answers:

Marianna [84]3 years ago

6 0

Answer:

Second option is correct. The x-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:5 is -2.

Step-by-step explanation:

From the given graph it is noticed that the endpoints of the line segment JK are J(-6,-2) and K(8,-9).

The formula to find x intercept.

$x=\frac{m}{m+n}(x_2-x_1)+x_1$

The ratio is 2:5, therefore the value of m is 2 and the value of n is 5.

$x=\frac{2}{2+5}(8-(-6))+(-6)$

$x=\frac{2}{7}(14)-6$

$x=4-6$

$x=-2$

Therefore the x-coordinate is -2 and second option is correct.

VLD [36.1K]3 years ago

5 0

Answer:

-2

Step-by-step explanation:

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3 years ago

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lora16 [44]

Answer:

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Step-by-step explanation:

8x² + 5 = 35

Subtract 5 from each side

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Divide each side by 8

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IRINA_888 [86]

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Step-by-step explanation:

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3/11 as a decimal using long division

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4 years ago

A checkers board is eight squares long and eight squares wide. The area of each square is 14 cm². Estimate the perimeter of the

Tamiku [17]

Answer:

Perimeter of the board is 119.7 cm.

Step-by-step explanation:

We are given that,

Area of each square = 14 cm²

i.e. $Side^2=14$

i.e. $Side= \sqrt{14}$

i.e Side = 3.74 cm

So, we get the side of each square is 3.74 cm.

Since, Perimeter of a square = $4a$

→ Perimeter of each square = $4\times 3.74$

→ Perimeter of each square = 14.96 cm

Since, there are 8×8= 64 squares on the board.

Thus, the perimeter of the board = 8 × Perimeter of each square.

i.e. Perimeter of the board = 8 × 14.96

i.e. Perimeter of the board = 119.68 cm

Hence, the perimeter of the board rounded to the tenths is 119.7 cm.

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