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2 years ago

Use algebra ,What number exceeds y by 4 less than x?

Mathematics

1 answer:

andriy [413]2 years ago

6 0

Answer:

y + (x-4)

Step-by-step explanation:

4 less than x= x-4

y exceeds 4 less than x = y + (x-4)

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John and his friend ordered lunch at a local sandwich shop. They each ordered a soft drink that costs $1.65. John orders a whole

ExtremeBDS [4]

Answer:

a. $12.54 = $ 1.65 + c/2 + c b. $ 7.26

Step-by-step explanation:

a. What equation can you use to find the cost c of a sandwich

Let c be the cost of a whole ham sandwich. Now, the total bill = cost of drinks + cost of half a ham sandwich + cost of a whole ham sandwich.

total bill = $ 12.54, cost of drinks = $ 1.65, cost of half a ham sandwich = c/2 and cost of a whole ham sandwich = c. So,

$12.54 = $ 1.65 + c/2 + c

b. What is the value of c

We then solve for c in the equation $12.54 = $ 1.65 + c/2 + c

collecting like terms, we have

$12.54 - $ 1.65 = c/2 + c

$ 10.89 = 3c/2

multiplying through by 2, we have

$ 10.89 × 2 = 3c

$ 21.78 = 3c

dividing through by 3, we have

c = $ 21.78/3

= $ 7.26

4 0

2 years ago

you have $895 in your checking account and write checks for $669, plus take $100 in cash out of your account. How much do you ha

Scilla [17]

To answer this we just need to set up a equation:-

895 - 669 - 100 = 126.

SO, after these transactions you will have $126 left.

Hope I helped ya!!

7 0

3 years ago

Math zoom join ends at 10:30 ID: 854 8913 6878<br> PASSCODE: 8yw2id hurry join be funny

Inessa05 [86]

no thanks but I'll see if I can get friends to join

8 0

3 years ago

Read 2 more answers

Suppose that the candy machine holds exactly 650 skittles, and every time someone inserts a quarter, exactly 7 skittles come out

Lady bird [3.3K]

Answer:

510 skittles left in the machine

Step-by-step explanation:

7 skittles x 20 quaters = 140 skittles taken out

650 - 140 = 510

7 0

2 years ago

According to data from a medical association, the rate of change in the number of hospital outpatient visits, in millions, in

GaryK [48]

Answer:

a) $f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient visits, in millions, is given by:

$f'(t)=0.001155t(t-1980)^{0.5}$

a) To find the function f(t) you integrate f(t):

$\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt$

To solve the integral you use:

$\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}$

Next, you replace in the integral:

$\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C$

Then, the function f(t) is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'$

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient visits.

Hence C' = 264,034,000

The function is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) For t = 2015 you have:

$f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7$

3 0

3 years ago