The answer is C ... or you could say n<3
Expand the expression as
(<em>s</em> + 1)³/<em>s</em> ⁵ = (<em>s</em> ³ + 3<em>s</em> ² + 3<em>s</em> + 1)/<em>s</em> ⁵
… = 1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵
Then taking the inverse transform, you get
LT⁻¹ [1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵]
… = LT⁻¹ [1/<em>s</em> ²] + LT⁻¹ [3/<em>s</em> ³] + LT⁻¹ [3/<em>s</em> ⁴] + LT⁻¹ [1/<em>s</em> ⁵]
… = LT⁻¹ [1!/<em>s</em> ²] + 3/2 LT⁻¹ [2!/<em>s</em> ³] + 1/2 LT⁻¹ [3!/<em>s</em> ⁴] + 1/24 LT⁻¹ [4!/<em>s</em> ⁵]
… = <em>t</em> + 3/2 <em>t</em> ² + 1/2 <em>t</em> ³ + 1/24 <em>t</em> ⁴
Answer:
yes he is correct because if you where to graph B it would have a greater slope
Step-by-step explanation:
-27x - 60 > 15x - 20
+27x +20 +27x +20
-40= 42x
-20
----- = x Is this correct?
21
Answer:
x1 =2-5i*sqrt(2)
x2 =2+5i*sqrt(2)
Step-by-step explanation:
-x^2 +4x-54=0 (quadratic equation)
a=-1, b=4, c=-54
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)
x1=(-4+sqrt(16-216))/(-2)
x1 =(-4+sqrt(-200))/(-2)
x1 =(-4+sqrt(200i^2))/(-2) i^2=-1
x1 =(-4+sqrt(100*2*i^2))/(-2)
x1 =(-4+10i*sqrt(2))/(-2)
x1 =2-5i*sqrt(2)
x2 =(-b-sqrt(b^2-4ac))/2a
x2 =(-4-10i*sqrt(2))/(-2)
x2 =2+5i*sqrt(2)
