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irina1246 [14]
3 years ago
14

If I ran 2/25 of a mile in 30 seconds how long would it take me to run 1 mile?

Mathematics
2 answers:
Leya [2.2K]3 years ago
8 0
You should get 375 seconds which is 6 1/4 of a minute or 6 minutes and 15 seconds
Andreas93 [3]3 years ago
6 0
Well to find this answer, we will have to find out how many pairs of 30 seconds there are in an hour. Since there are 60 minutes in an hour, and there are 30 seconds in a minute, we can conclude that there are 120 pairs of 30 seconds in an hour. So our equation would be 2/25 × 120. So our answer would be that you could run 9 and 3/5 of a mile in one hour. hope I helped!
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It is 28350 merry Christmas
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3 years ago
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In a 30-60-90 degree right triangle, the side opposite the 30-degree angle is
Afina-wow [57]

Answer:

It is the short leg.

Step-by-step explanation:

The triangle and is called a right triangle and the side opposite the 30-degree angle is the shorter leg

6 0
3 years ago
The rate at which a duck gains weight is proportional to the difference between its adult weight and its current weight. At time
kogti [31]
DB/dt = 1/5(100 - B)
5/(100 - B) dB = dt
-5 ln (100 - B) = t + C
Since B(0) = 20, then
-5 ln (100 - 20) = C
i.e. C = -5 ln 80

Thus -5 ln (100 - B) = t - 5 ln 80
or t = 5 ln 80 - 5 ln (100 - B) = 5 ln (80 / (100 - B))

When the weight = 40 grams
t = 5 In (80 / 100 - 40) = 5 In (80 / 60) = 5 ln (4/3) = 1.438 days
Rate of weight gain = 40 / 1.438 = 27.8 grams per day

When the weight = 70 grams
t = 5 ln (80 / 100 - 70) = 5 ln (80 / 30) = 5 ln (8/3) = 4.9 days
Rate of weight gain = 70/4.9 = 14.27 grams per day.

Therefore, the duck gains weight faster when it weighs 40 grams.
6 0
3 years ago
Class A has 11 pupils and class B has 15 pupils.
Pavlova-9 [17]

Answer:

The mean score in the math test for class B=28.47

Step-by-step explanation:

<em>Step 1: Determine the total number of students in both Classes</em>

Total number of students=number in class A+number in class B

where;

number in class A=11 pupils

number in class B=15 pupils

replacing;

Total number of students=11+15=26 students

<em>Step 2: Determine total score for both classes</em>

Total score for both classes=total score for class A+total score for class B

total score for both classes=mean score for both classes×total number of students

total score for both classes=(49×26)=1,274

total score for class A=mean score for class A×total number of class A students

total score for class A=(77×11)=847

total score for class B=mean score for class B×total number of class B students

total score for class B=m×15=15 m

replacing;

1,274=847+15 m

15 m=1,274-847

15 m=427

m=427/15=28.47

The mean score in the math test for class B=28.47

7 0
3 years ago
Solve Proportions In the following exercises, solve.
Julli [10]

Answer:

Thus, a golden retriever should be given 19 teaspoon of medicine.

Step-by-step explanation:

  • Given that a golden retriever weighing 85 pounds has diarrhea. His medicine is prescribed as 1 teaspoon per 5 pounds.
  • To find how much medicine should he be given.
  • Assign a variable. Write a sentence that gives the information to find it.
  • Translate into a proportion be careful of the units.
  • Multiply both sides by the  Least Common Denominator and simplify. Check the answer.

Step 1 of 3

Write the data in mathematical form and simplify.

Let x=the number of teaspoon

If 1  teaspoon medicine is 5  pounds then 85  pounds is how many teaspoon of medicine.

Translate the statement into proportion.

\begin{aligned}\frac{\text { pounds }}{\text { teaspoon }} &=\frac{\text { pounds }}{\text { teaspoon }} \\\frac{5}{1} &=\frac{85}{x}\end{aligned}

Step 2 of 3

Multiply both sides by x and simplify

$x(5)=\frac{85}{\bcancel{x}}(\bcancel{x})

5x=85

Divide by 5,

x=\frac{85}{5}

<em>Simplify, x=19</em>

<em>Step 3 of 3</em>

<em>Check the answer.</em>

<em>Substitute x=19  in original proportion and simplify.</em>

<em />$$\begin{aligned}\frac{5}{1} &=\frac{85}{x} \\5 &=\frac{85}{19}\end{aligned}$\\ \\ Hence, $5=5$, True

5 0
2 years ago
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