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nasty-shy [4]
3 years ago
11

Which expression can be simplified by applying the additive inverse property

Mathematics
2 answers:
Ksju [112]3 years ago
6 0

We have to identify the expression in which Additive inverse identity is applied.

Additive inverse property states that "The additive inverse of a number 'x' is a number that when it is added to 'x', yields zero".

Consider the first expression,

A. -329-164+513+206+(-164)

There are no such numbers, which will yield zero on addition. Hence, additive inverse property is not applied here.

B. 1.6+0.2-1.8-0.5

There are no such numbers, which will yield zero on addition. Hence, additive inverse property is not applied here.

C. -\frac{7}{10}-\frac{3}{4}+1\frac{1}{2}+(-\frac{7}{10})

There are no such numbers, which will yield zero on addition. Hence, additive inverse property is not applied here.

D. 9\frac{3}{4}\+4\frac{5}{8}+(-9\frac{3}{4}+(2\frac{3}{5})

Here, 9\frac{3}{4} when added to -9\frac{3}{4} will yield zero. Therefore, -9\frac{3}{4} is the additive inverse of 9\frac{3}{4}.

So, in option D, Additive inverse property is applied.


harina [27]3 years ago
4 0
D, because 9 3/4 and -9 3/4 cancel out to 0, which is the additive inverse property.
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Answer:

Step-by-step explanation:

With a slope of 1 and a y intercept of -3

y = 1x - 3

y = 1(-2) - 3

y = -5

(-2, -5)

6 0
2 years ago
What eqauls to 31.25
RSB [31]

125 = 5^3 = 25 * 5

4 \cdot \sqrt{125} = 4 \sqrt{25 \cdot 5} = 4 \cdot 5 \sqrt{5} = 20\sqrt{5}

The simplification you are trying to do involves finding the prime factorization of a number. Since 125 is not divisible by 2, move on to 3. 125 is also not divisible by 3, so move on to 5. Then 125/5 = 25, and 25/5 = 5, so 125 = 5^3. The prime factorization of 125 is 5^3.

5 0
3 years ago
Read 2 more answers
Evaluate<br> 2x - Y when x= 5, y=3
Allushta [10]

Answer:

the answer is 7

Step-by-step explanation:

2x-y

2*5 - 3

10 - 3

7                                  

7 0
2 years ago
Seleccione el número que se puede<br> describir mejor como enteros.
Zielflug [23.3K]

the second one

Step-by-step explanation:

7 0
1 year ago
A company has 200 machines. Each machine has 129 probability of not working. If you were to pick 40 machines randomly, the proba
alexgriva [62]

The probability that 5 would not be working is 0.18665, the probability that at least one machine would be working is 0.00602 and the probability that all would be working is 1.

Given a company has 200 machines. Each machine has a 12% probability of not working.

If we working pick 40 machines randomly then we have to find the probability that 5 would not be working, the probability that at least one machine would be working, and the probability that all would be working.

So

1) probability that 5 would not be working

C(40,5)·0.12⁵·0.88³⁵= 40!/(5!(40-5)!)·0.12⁵·0.88³⁵

                                ≈ 0.18665

2)  probability that at least one machine would be working

0.88⁴⁰ ≈ 0.00602

3) probability that all would be working

1 - 0.12⁴⁰ ≈ 1.0000

Learn more about probability here: brainly.com/question/24756209

#SPJ10

7 0
1 year ago
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