The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
Answer:
Part 1 = $1.32
Step-by-step explanation:
.72 divided by 6 is 12. So they make 12 cents per ticket, so that means you would have to do 12 times 11 and that should get you 132 cents and that is equivalent to $1.32.
Answer:
x >= 20
Step-by-step explanation:
Solve for x:
Start to isolate x by subtracting the 6 from both sides.
Then multiply 10 from each side.
After that, you would get x >= 20
The answer -35.5 Hope this helps you
9514 1404 393
Answer:
y' = -sin(x)
Step-by-step explanation:
Your table of derivatives of trig functions tells you the derivative of the cosine is the opposite of the sine.
dy/dx = -sin(x)