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3 years ago

5

The Width of a rectangle is 2w+3. The length is equal to 4 times its width. Write an expression to represent the perimeter of th

e rectangle. Show how you determined your expression.

1 answer:

kupik [55]3 years ago

4 0

Since the perimeter is the sum of the length of all sides we multiply width and length by 2 and then add them together

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Mr.Choi has a class of 17 students. He can spend $17 on each student to buy math supplies for the year. He first bugs all his st

Reika [66]

Multiply 17(number of students) and 17(amount he’s spending on each student)
So 17x17=289
Then subtract what he used which is 97.41
So 289-97.41= 191.59

He has $191.59 left

5 0

3 years ago

Help ASAP!!! 3/8 of the seventh grade students were taking Advanced math at the beginning of the year, but Seven dropped out by

Rashid [163]

Answer:

There are 392 students in the seventh grade.

Step-by-step explanation:

Let us assume that there are x number of students in the seventh grade.

Now, 3/8 of the seventh grade students were taking Advanced math at the beginning of the year, but seven dropped out by the end of the year.

So, after the end of the year there were $(\frac{3}{8}x - 7)$ number of students taking advanced math.

So, as per given condition, $(\frac{3}{8}x - 7) = 140$

⇒ $\frac{3}{8}x = 147$

⇒ x = 392

Therefore, there are 392 students in the seventh grade. (Answer)

8 0

3 years ago

Is 56/7 a rational number or

Sati [7]

Answer:

Yes

Step-by-step explanation:

The definition of a rational number is a number that can be represented as a fraction. Since 56/7 is a fraction it must be a rational number. An irrational number is a number that cannot be represented as a fraction because it never ends and repeats without a pattern forever. An example of this is pi because pi can never exactly be represented as a fraction.

4 0

2 years ago

Factor completely, then place the answer in the proper location on the grid.

Tresset [83]

$\mathrm{Factor\:out\:common\:term\:}9 \ \textgreater \ 9\left(x^4-25y^8\right)$

$Factor \ \textgreater \ x^4-25y^8$

$\mathrm{Apply\:difference\:of\:squares\:rule:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)$
$x^2-5y^4=\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)$

$x^2-5y^4 \ \textgreater \ \mathrm{Apply\:difference\:of\:squares\:rule:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)$
$x^2-5y^4=\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)$

$\left(x^2+5y^4\right)\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)$

$9\left(x^2+5y^4\right)\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)$

Hope this helps!

8 0

3 years ago

A boat traveled 147 miles downstream and back. The trip downstream took 7 hours. The trip back took 147 hours. Find the speed of

KonstantinChe [14]

Answer:

The speed of boat in still water is 11 miles per hour

The speed of current is 10 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by boat in downstream = $d_1$ = 147 miles

The time taken by boat in downstream trip = $t_1$ = 7 hours

The distance cover by boat in upstream = $d_2$ = 147 miles

The time taken by boat in upstream trip = $t_2$ = 147 hours

Let The speed of boat in still water = $s_1$ = x mph

And The speed of the current = $s_2$ = y mph

Now, According to question

Speed = $\dfrac{\textrm Distance}{\textrm Time}$

For downstream

$s_1$ + $s_2$ = $\dfrac{d_1}{t_1}$

or, x + y = $\dfrac{147}{7}$

I.e x + y = 21 mph ..........1

For upstream

$s_1$ + $s_2$ = $\dfrac{d_2}{t_2}$

or, x - y = $\dfrac{147}{147}$

I.e x - y = 1 mph ..........2

Now, Solving Eq 1 and 2

I.e (x + y) + (x - y) = 21 + 1

Or, (x + x) + (y - y) = 22

Or, 2 x = 22

∴ x = $\frac{22}{2}$

I.e x = 11 mph

So, speed of boat = x = 11 miles per hour

Again, put The value of x in Eq 2

So, x - y = 1 mph

I.e 11 - y = 1

∴, y = 11 - 1

I.e y = 10 mph

So, speed of current = y = 10 miles per hour

Hence The speed of boat in still water is 11 miles per hour , and The speed of current is 10 miles per hour . Answer

3 0

3 years ago