4/5 dived by 3/4<br><br> Please help

As part of a community-service project, a local club has decided to paint 864 walls across town. The club has 36 volunteers. If

tankabanditka [31]

Answer:

24 walls per volunteers

Step-by-step explanation:

given that there are 864 walls and that there are 36 volunteers

if the walls are divided evenly over the 36 volunteers,

each volunteer would paint,

= 864 walls ÷ 36 volunteers

= 24 walls per volunteers

4 0

3 years ago

A grasshopper jumps straight up from the ground with an initial vertical velocity of 8 feet per second. After how many seconds w

vlabodo [156]

Answer:

Problem 1 : After 0.25 s

Problem 2 : The squirrel doesn't reach the ground before the nut

Step-by-step explanation:

Problem 1

This is a standard physics problem

The equation that defines the movement of the grasshopper given the initial velocity, and the acceleration is the following

Distance = Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 0, because the grasshopper is on the ground and we choose the reference system there)

Vo is the initial velocity = 8 feet/sec

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 = - 32.174 feet per second per second.)

t is the time

We substitute in the equation, and solve for t (time)

Distance = Do + Vo*t + 0.5*a*t^2

(1 foot)= (0)+ (8 feet/s)*t + 0.5*(-32.174 feet/s^2)*t^2

Solving this equation, we get that

t = 0.25 s

Problem 2

This problem is similar to the previous one

We apply the same formula

D = Do + Vo*t + 0.5*a*t^2

But in this case, we are going in the opposite direction, and we have an initial distance.

Do = 27 feet

Vo is the initial velocity of the nut = -6 feet/s

D = 0 (Ground)

We substitute in the equation, and solve for t (time)

(0) = (27) + (-6 feet/s)*t + 0.5*(-32 feet/s^2)*t^2

t = 1.125 s < 2s

The nut reaches ground in 1.125 s, so the squirrel doesn't reach the ground before the nut

4 0

3 years ago

Frank cut a 52 inch string into 3 pieces. The first piece is 20 inches long. The second piece is at least 12 inches long, but no

Eddi Din [679]

We need to figure out how much string would be left, after taking away the first two pieces.
We know that the first piece is 20 inches long, so we can say that there is 52-20 inches left, or 32 inches.

The second piece is between 12 and 18 inches, meaning that there would be between 32-12 and 32-18 inches left for the third piece, or 20 and 14 inches. This means that the third piece would be at least 14 inches long, but no more than 20, since we don’t have more string than that (20+12+20=52, and 20+14+18=52)

So we can say that x is greater or equal to 14, but less than or equal to 20, or:

14<=x<=20 (“<=“ is written like a normal “<“ sign with a line _ right under it)

4 0

3 years ago

Which values satisfy the inequality? |x| < 3 Choose all answers that are correct. A. x = –6 B. x = –5 C. x = –1 D. x = 2

ahrayia [7]

Lets plug in the answer choices and see which one works

A. x = -6

| -6 | < 3
6 < 3

False, so A is not the answer

B. x = -5

| -5 | < 3
5 < 3

False, so B isn't the answer

C. x = -1

| -1 | < 3
1 < 3

True, so C is the answer.

But lets just check D to make sure C is the answer.

D. x = 2

| 2 | < 3
2 < 3

False, so D isn't the answer either.

C is your answer :)

4 0

3 years ago

Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v

Veronika [31]

Answer:

$\text {CI} = (60.54, \: 81.46)\\\\$

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

$\bar{x} = \$71$

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

$s = \$ 22.35$

The confidence interval is given by

$\text {confidence interval} = \bar{x} \pm MoE\\\\$

Where the margin of error is given by

$$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\$

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and $t_{\alpha/2}$ is the t-score corresponding to a 95% confidence level.