Hey this is very easy to learn! So to express a decimal as a percent all we have to do is multiply it by 100. So multiplying .053 by 100 would just mean moving the decimal point 2 spaces to the right.
So the answer would be 5.3%
I hope this helps!
-Ayden
We have been given two functions 
and 
. We are asked to find 
.
We will use composite function property 
to solve our given problem.
Now we will combine like terms as:
Therefore, the value of would be 
.
Answer:
The first thing you do is:
Step-by-step explanation:
How to calculate 60 divided by 19
Here we will show you step-by-step with detailed explanation how to calculate 60 divided by 19 using long division.
Before you continue, note that in the problem 60 divided by 19, the numbers are defined as follows:
60 = dividend
19 = divisor
Step 1:
Start by setting it up with the divisor 19 on the left side and the dividend 60 on the right side like this:
1 9 ⟌ 6 0
Step 2:
The divisor (19) goes into the first digit of the dividend (6), 0 time(s). Therefore, put 0 on top:
0
1 9 ⟌ 6 0
Step 3:
Multiply the divisor by the result in the previous step (19 x 0 = 0) and write that answer below the dividend.
0
1 9 ⟌ 6 0
0
Step 4:
Subtract the result in the previous step from the first digit of the dividend (6 - 0 = 6) and write the answer below.
0
1 9 ⟌ 6 0
- 0
6
Step 5:
Move down the 2nd digit of the dividend (0) like this:
0
1 9 ⟌ 6 0
- 0
6 0
Step 6:
The divisor (19) goes into the bottom number (60), 3 time(s). Therefore, put 3 on top:
0 3
1 9 ⟌ 6 0
- 0
6 0
Step 7:
Multiply the divisor by the result in the previous step (19 x 3 = 57) and write that answer at the bottom:
0 3
1 9 ⟌ 6 0
- 0
6 0
5 7
Step 8:
Subtract the result in the previous step from the number written above it. (60 - 57 = 3) and write the answer at the bottom.
0 3
1 9 ⟌ 6 0
- 0
6 0
- 5 7
3
꙰ Hello there mohammedsaquibali45 ! My Name is ⚝Tobie⚝ and I'm glad you asked! Let me walk you step by step in order to comprehend the question better! ꙰
i
{x}^{2}-5x-10x+50
x
2
−5x−10x+50
ii Collect like terms.
{x}^{2}+(-5x-10x)+50
x
2
+(−5x−10x)+50
iii Simplify.
{x}^{2}-15x+50
x
2
−15x+50
Area of a circle = πr^2
Area of a sector with angle x° = (x/360) πr^2
For the smaller sector,
x = 30°
r = 6 in
Required area of sector = (30/360) × π × 6^2 = 9.424 in^2
To the nearest hundreth, Area = 9.42 in^2
