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2 years ago

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The number of sticks of gum varies directly as the number of packages. There are 36 sticks of gum in 2 packages. Suppose you hav

e 5 packages of gum. The direct variation equation to determine how many sticks you have is ________giving you _______sticks of gum

1 answer:

tangare [24]2 years ago

8 0

Answer:

Each packet gives you 18 sticks of gum. If you asked how many in 5 packets it would be 90 sticks.

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In your own words describe surface and area

Oksana_A [137]

Answer:

Hi there!

Surface~ is the outside part, uppermost area

Area~ the extent or measurement of a surface

8 0

2 years ago

Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes o

Volgvan

Answer:

$\frac{4}{15} \\$

Step-by-step explanation:

number of the students like brussels sprouts but dislike lima beans = number of these students who dislike lima beans - number of students who dislike lima beans and also dislike brussels sprouts

$\frac{2}{3}-\frac{3}{5}* \frac{2}{3} = \frac{2}{3}-\frac{6}{15}=\frac{10}{15}-\frac{6}{15}=\frac{4}{15}\\$

8 0

3 years ago

If a line has a slope of 9/5. If one of the points on the line is (-10, -16), which could be another point?

zlopas [31]

Answer:

(–5, –7)

Step-by-step explanation:

From the question given above, the following data were obtained:

Slope = 9/5

Coordinate 1 = (–10, –16)

x₁ = –10

y₁ = –16

Coordinate 2 = (x₂, y₂)

Next, we shall determine the change in x and y coordinate. This can be obtained as follow:

Slope = change in y–coordinate / change in x–coordinate

Slope = Δy / Δx

Slope = 9/5

9/5 = Δy / Δx

Thus,

Δy = 9

Δx = 5

Next, we shall determine the second coordinates as follow:

Δy = y₂ – y₁

Δx = x₂ – x₁

For x–coordinate:

x₁ = –10

Δx = 5

Δx = x₂ – x₁

5 = x₂ – (–10)

5 = x₂ + 10

Collect like terms

x₂ = 5 – 10

x₂ = – 5

For y–coordinate:

y₁ = –16

Δy = 9

Δy = y₂ – y₁

9 = y₂ – (–16)

9 = y₂ + 16

Collect like terms

y₂ = 9 – 16

y₂ = – 7

Coordinate 2 = (x₂, y₂)

Coordinate 2 = (–5, –7)

6 0

2 years ago

Molly was on a long 136 mile road trip. The first part of the trip there was lots of traffic, she only averaged 16 mph. The seco

Mazyrski [523]

Answer:

In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

Explanation:

Given that the road trip was 136 miles;

$d=136$

The first part of the trip there was lots of traffic, she only averaged 16 mph;

$v_1=16$

The second part of the trip there was no traffic so she could drive 44 mph;

$v_2=44$

She traveled for a total of 5 hours;

$t=5$

let x represent the time in traffic when she traveled at 16 mph

$t_1=x$

the time the traffic is clear would be;

$t_2=t-t_1=5-x$

Recall that distance equals speed multiply by time;

$d=v_1t_1_{}_{}^{}+v_2t_2$

substituting the values;

$136=16x+44(5-x)$

solving for x;

$\begin{gathered} 136=16x+220-44x \\ 44x-16x=220-136 \\ 28x=84 \\ x=\frac{84}{28} \\ x=3 \end{gathered}$

So;

$\begin{gathered} t_1=3\text{ hours} \\ t_2=5-x=5-3=2 \\ t_2=2\text{ hours} \end{gathered}$

Therefore, In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

7 0

1 year ago

What is the mean and median of the data<br><br> 4.7,8.51,6.5,7.42,9.64,7.2,9.3

Savatey [412]

Answer:Median=7.42

Mean=7.61

Step-by-step explanation:

4 0

1 year ago