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scZoUnD [109]
3 years ago
14

Which of the following is the solution to the equation x^2-36x=0

Mathematics
2 answers:
Marizza181 [45]3 years ago
7 0
x^2-36x=0 \\
x(x-36)=0 \\
x=0 \ \lor \ x-36=0 \\
x=0 \ \lor \ x=36 \\
\boxed{x=0 \hbox{ or } x=36}
Inessa05 [86]3 years ago
3 0
x^2-36x=0\\
x(x-36)=0\\
x=0 \vee x=36
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Step-by-step explanation:

The equation of a circle is given by

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For the circle in this problem, we know that:

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We also know that the circle passes through the point (-3,2), therefore we can calculate the radius as the distance between the point on the circle and the center of the circle:

r=\sqrt{(-3-(5))^2+(2-(-4))^2}=\sqrt{(-8)^2+(6)^2}=\sqrt{64+36}=10

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Learn more about circles:

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