<span> It would depend on the number of rows?
This is an arithmetic sequence and the sum of n terms is -->
n/2(2a+(n-1)d), where a is the first term and d is the common
difference. In this case a = 10, d =6
n/2(20+6(n-1)) = 3n^2 + 7n = ANSWER
n = number of rows
</span>
Answer: The number would be 18
Step-by-step explanation:
18/2=9 9-3=6 6*3=18
Answer:
0.0045248 ;
0.1312218 ;
0.0001809 ;
0.1659729
Step-by-step explanation:
Number of Kings in deck = 4
Total number of cards in deck = 52
Picking without replacement :
A = King on first draw :
P(A) = 4 / 52
A = King on 2nd draw :
P(B) = 3 / 51
A = King on 3rd draw :
P(C) = 2 / 50
1.) P(A n B) = P(A) * P(B)
P(A n B) = 4/52 * 3/51 = 12 / 2652 = 0.0045248
2.) P(A u B) = P(A) + P(B) - P(AnB)
P(AuB) = 4/52 + 3/51 - 0.0045248 = 0.1312218
3.) P(A ∩ B ∩ C) = P(A) * P(B) * P(C)
P(A ∩ B ∩ C) = 4/52 * 3/51 * 2/50 = 0.0001809
4.) P(A U B U C) =
P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) - P(AnBnC)
P(AnC) = P(A) * P(C) = 4/52 * 2/50 = 0.0030769
P(BnC) = P(B) * P(C) = 3/51 * 2/50 = 0.0023529
4/52 + 3/51 + 2/50 - 0.0045248 - 0.0030769 - 0.0023529 + 0.0001809 = 0.1659729
From the given, it is stated that after Amelia took 14 out of the box, Ramon took half of those which remained and he had 16 tiles. The number of tiles left after Amelia took hers is equal to twice of 16 which is equal to 32 tiles.
To determine the number of tiles during the start, we can add the 14 tiles from the calculated 32 tiles.
n = 14 tiles + 32 tiles
n = 46 tiles
<em>Answer: 46 tiles</em>
9.66 - you just multiple 6 by 1.61
