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Gelneren [198K]
3 years ago
11

A company has 8 mechanics and 6 electricians. If an employee is selected at random, what is the probability that they are an ele

ctrician
Mathematics
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

Probability = \frac{3}{7}

Step-by-step explanation:

Given

Electrician = 6

Mechanic = 8

Required

Determine the probability of selecting an electrician

First, we need the total number of employees;

Total = n(Electrician) + n(Mechanic)

Total = 6 + 8

Total = 14

Next, is to determine the required probability using the following formula;

Probability = \frac{n(Electrician)}{Total}

Probability = \frac{6}{14}

Divide numerator and denominator by 2

Probability = \frac{3}{7}

<em>Hence, the probability of selecting an electrician is 3/7</em>

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In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?
erica [24]

In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?

Answer:

BD = c*sin(A)

BD = c*cos(B)

BD = b*tan(A)

Step-by-step explanation:

∆ABD is a right triangle.

Recall: trigonometric ratios of any right triangle can easily be understood or remembered with the acronym, SOHCAHTOA.

SOH => sin(θ) = opposite/hypotenuse

CAH => Cos(θ) = adjacent/hypotenuse

TOA = tan(θ) = opposite/adjacent

Thus, the length of segment BD, in terms of trigonometric ratios for ∆ABD can be done as follows:

Let BD = x

AB = c

AD = b

=>The sine ratio for the length of line segment BD = x, using SOH.

θ = A

Opposite = DB = x

hypotenuse = AB = c

sin(A) = \frac{x}{c}

Make x the subject of formula.

c*sin(A) = x

BD = x = c*sin(A)

=>The Cosine ratio for the length of line segment BD = x, using CAH

θ = B

Adjacent = DB = x

hypotenuse = AB = c

cos(B) = \frac{x}{c}

Make x the subject of formula.

c*cos(B) = x

BD = x = c*cos(B)

=>The Tangent ratio for the length of line segment BD = x, using TOA

θ = A

Adjacent = DB = x

hypotenuse = AD = b

tan(A) = \frac{x}{b}

Make x the subject of formula.

b*tan(A) = x

BD = x = b*tan(A)

5 0
3 years ago
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