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3 years ago

Which lists all the integer solutions of the equation |x| = 4?

Mathematics

2 answers:

Harlamova29_29 [7]3 years ago

6 0

Umm well Idk if im right but to me i think it is D

Natasha2012 [34]3 years ago

5 0

A because the absolute value is how many spaces the number is away from 0. So it could either be 4 or -4, because both of these are 4 spaces away from zero.

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I'm doing Quadratic formula and I've simplified it down to the equation at the bottom. What do I do after? Is that my answer bec

givi [52]

No you could have left it as the last but one line or write them separately as

11/18 + √85 / 18 , 11/18 - √85/18

6 0

3 years ago

Find the value of X, rounded to the nearest tenth. <br> A. 31.8<br> B. 31.4<br> C. 10.3<br> D. 10.7

Molodets [167]

Answer:

31.4

Step-by-step explanation:

x=18/sin35

x= 31.38

=31.4(nearest tenth )

4 0

2 years ago

(PLEASE HELP)<br> Which value of x makes this equation true<br> -90=-100+x

riadik2000 [5.3K]

Answer:

-0.9

Step-by-step explanation:

-0.9 × 100 = -90

8 0

2 years ago

Read 2 more answers

three hens lay 3 eggs any 3 days. in how many days will 3n hens lay at this rate 9nk eggs? please i need answer fast!!! will giv

dangina [55]

If three hens lay 3 eggs any 3 days. The number of days that 3 Hens give in 9 eggs is: 9days.

<h3>Number of days that three hens lay 9 eggs</h3>

Given:

3 hens lay 3 eggs in 3 days

First step is to determine the number of egg one hen lay in 3 days

1 hen in 3 days lays 3/3

1 hen in 3 days lays=1 egg

Second step is to determine the number of egg 3 hens lay 1 day

1 hen in 1 day lays 1/3 egg

3 hens in 1day lay=(1×3)/3

3 hens in 1day lay=1 egg

Third step is to determine the number of eggs 3 hens lay in 9 days

3 hens in 9 days lay=(1×9)

3 hens in 9 days lay=9 eggs

Therefore assuming three hens lay 3 eggs any 3 days. The number of days that 3 Hens give in 9 eggs is: 9days.

Learn more about number of days that three hens lay 9 eggs here: brainly.com/question/9286901

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7 0

1 year ago

The coordinates of a particle in the metric xy-plane are differentiable functions of time t with:

frez [133]

Answer:

The rate of change of the distance $\frac{ds}{dt}$ when x = 9 and y = 12 is $-7.6\:\frac{m}{s}$ .

Step-by-step explanation:

This is an example of a related rate problem. A related rate problem is a problem in which we know one of the rates of change at a given instant $\frac{dx}{dt}$ and we want to find the other rate $\frac{dy}{dt}$ at that instant.

We know the rate of change of x-coordinate and y-coordinate:

$\frac{dx}{dt}=-2\:\frac{m}{s} \\\\\frac{dy}{dt}=-8\:\frac{m}{s}$

We want to find the rate of change of the distance $\frac{ds}{dt}$ when x = 9 and y = 12.

The distance of a point (x, y) and the origin is calculated by:

$s=\sqrt{x^2+y^2}$

We need to use the concept of implicit differentiation, we differentiate each side of an equation with two variables by treating one of the variables as a function of the other.

If we apply implicit differentiation in the formula of the distance we get

$s=\sqrt{x^2+y^2}\\\\s^2=x^2+y^2\\\\2s\frac{ds}{dt}= 2x\frac{dx}{dt}+2y\frac{dy}{dt}\\\\\frac{ds}{dt}=\frac{1}{s}(x\frac{dx}{dt}+y\frac{dy}{dt})$

Substituting the values we know into the above formula

$s=\sqrt{9^2+12^2}=15$

$\frac{ds}{dt}=\frac{1}{15}(9(-2)+12(-8))\\\\\frac{ds}{dt}=\frac{1}{15}\left(-18-96\right)\\\\\frac{ds}{dt}=\frac{1}{15}(-114)=-\frac{38}{5}=-7.6\:\frac{m}{s}$

The rate of change of the distance $\frac{ds}{dt}$ when x = 9 and y = 12 is $-7.6\:\frac{m}{s}$

7 0

3 years ago