182 divided by 2 is 93.Then you subtract 32 from 93 and get 61.SO they two numbers you are looking for is 93 and 61
<span>The graph would be translated 5 units right and 1 unit up, giving an upward facing parabola with a vertex at (5, 1).
Explanation:
Since 5 was subtracted from x before it was squared, this means a horizontal translation 5 units. Since it was subtracted, this means it was translated right 5 units.
The 1 added at the end means it was translated 1 unit up as well.
This is in vertex form, y=a(x-h)^2 + k, where (h, k) is the vertex; h corresponds with 5 and k corresponds with 1, so the vertex is at (5, 1).</span>
Answer:
192
Step-by-step explanation:
12.5% is 24.
So 100% will be (100/12.5) x 24 = 192.
Done.
Answer:
Center: (-2, 4)
Radius: 4
Step-by-step explanation:
To find the centre and radius, we require to identify g , f and c
By comparing the coefficients of 'like terms' in the given equation with the general form.
2g = 4 → g = 2 , 2f = -8 → f = -4 and c = 4 → center=(−g,−f)=(−2,4)
radius = √22+(−4)2−4= √4+16−4=4
Center: (-2, 4)
Radius: 4
Hope This Helps! :)
For the sake of example, let's multiply the two numbers
![2.3 \times 10^5](https://tex.z-dn.net/?f=2.3%20%5Ctimes%2010%5E5%20)
and
![3.5 \times 10^7](https://tex.z-dn.net/?f=3.5%20%5Ctimes%2010%5E7)
together. Altogether, we have:
![2.3\times10^5\times3.5\times10^7](https://tex.z-dn.net/?f=2.3%5Ctimes10%5E5%5Ctimes3.5%5Ctimes10%5E7)
Rearranging the expression, we can group the exponents and coefficients together:
![2.3\times3.5\times10^5\times10^7](https://tex.z-dn.net/?f=2.3%5Ctimes3.5%5Ctimes10%5E5%5Ctimes10%5E7)
Multiplying each out, we notice that since
![10^5](https://tex.z-dn.net/?f=10%5E5)
and
![10^7](https://tex.z-dn.net/?f=10%5E7)
have the same base (10), multiplying them has the effect of adding their exponents, which leaves us with:
![2.3\times3.5\times10^{5+7}=8.05\times10^{12}](https://tex.z-dn.net/?f=2.3%5Ctimes3.5%5Ctimes10%5E%7B5%2B7%7D%3D8.05%5Ctimes10%5E%7B12%7D)
The takeaway here is that multiplying two numbers in scientific notation together has the effect of multiplying its coefficients and <em>adding</em> its exponents.