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wel
3 years ago
5

Adratic Formula

Mathematics
2 answers:
anastassius [24]3 years ago
7 0

Answer:

There are no real solutions for the equation x^{2}+5x+7.

Step-by-step explanation:

For a quadratic equation given by ax^{2}+bx+c=0

The number of real solutions are determined by discriminant D.

D=b^{2}-4ac

if D>0 then the roots are real and distinct

if D=0 then roots are real and equal

if D<0 then real roots do not exist.

In this case,

a=1 b=5 and c=7

D=b^{2}-4ac=5^{2}-4\times1\times7=-3 < 0

Since D<0, there are no real solutions.

maw [93]3 years ago
5 0

Answer:

Step-by-step explanation:

discriminant=5²-4×1×7=25-28=-3<0

no real number solution.

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