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3 years ago

Adratic Formula

Mathematics

2 answers:

anastassius [24]3 years ago

7 0

Answer:

There are no real solutions for the equation $x^{2}+5x+7$ .

Step-by-step explanation:

For a quadratic equation given by $ax^{2}+bx+c=0$

The number of real solutions are determined by discriminant D.

D= $b^{2}-4ac$

if D>0 then the roots are real and distinct

if D=0 then roots are real and equal

if D<0 then real roots do not exist.

In this case,

a=1 b=5 and c=7

$D=b^{2}-4ac=5^{2}-4\times1\times7=-3 < 0$

Since D<0, there are no real solutions.

maw [93]3 years ago

5 0

Answer:

Step-by-step explanation:

discriminant=5²-4×1×7=25-28=-3<0

no real number solution.

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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JulijaS [17]

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2 years ago

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Answer:

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