- It's very long so I'm not giving answers but here's how i would do it:
- use Pythagoras
where c is the longest side - use sine rule
where lower cases are the sides, and capitals are their opposite angles.
e.g for 15:
a = 3, b is missing, c = 10
A is missing, B is ?, C is 90
Answer:
5 verticles
Step-by-step explanation:
<span>Another answer:
According to the figure, the coordinates of JKLM are, J(-7,-2), K(-4,-2), L(-2,-5) and M(-9,-5)
JKLM is translated to J'K'L'M' by means of the rule (x+8, y-3), we should know that (x, y) are coordinates of the pre image, to find the coordinates of each image we have (x', y') such that
x' =x+8, and y' =y-3. Therefore, the coordinates of L' can be found by L'(-2+8, -5-3)=(6, -8)
the final answer is L'(6, -8).</span>
Answer:
6x-4
Step-by-step explanation:
Let's simplify step-by-step.
2(3x−2)−(4x−4x)
Distribute the Negative Sign:
=2(3x−2)+−1(4x−4x)
=2(3x−2)+−1(4x)+−1(−4x)
=2(3x−2)+−4x+4x
Distribute:
=(2)(3x)+(2)(−2)+−4x+4x
=6x+−4+−4x+4x
Combine Like Terms:
=6x+−4+−4x+4x
=(6x+−4x+4x)+(−4)
=6x+−4
Answer:
=6x−4
