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weeeeeb [17]
3 years ago
12

Of the 32 students in a class, 18 play the violin, 16 play the piano, and 7 play neither.

Mathematics
1 answer:
german3 years ago
3 0

Answer:

(a)9

(b)I. 0.28125

II. 0.46875

III. 0.25

Step-by-step explanation:

There are a total of 32 students, therefore the number of elements in the Universal set, n(U)=32

1$8 play the violin, n(V)=18\\16 play the piano, n(P)=16\\ 7 play neither, n(P \cup V)' =7

(a)The Venn diagram is attached below.

n(U)=n(V)+n(P)-n(V \cap P)+ n(P \cup V)'\\32=18+16+7-n(V \cap P)\\32=41-n(V \cap P)\\n(V \cap P)=41-32\\n(V \cap P)=9\\

Therefore, 9 students play both the violin and  piano.

(b)

I. Probability that the student  plays the violin but not the piano

Number of Students who play violin only =18-x=18-9=9

P(V \cap P') = \dfrac{n(V \cap P')}{n(U)}\\= \dfrac{9}{32}\\=0.28125

ii.Probability that the student does not play the violin

Number of Students who does not play violin only =17-x+7=17-9+7=15

P(does not play violin only)

= \dfrac{15}{32}\\=0.46875

iii.Probability that the student plays the piano but not the violin

Number of Students who play piano only =17-x=17-9=8

P(V' \cap P) = \dfrac{n(V' \cap P)}{n(U)}\\= \dfrac{8}{32}\\\\=0.25

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From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean leng
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Complete Question

From a random sample of size 18, a researcher states that (11.1, 15.7) inches is a 90% confidence interval for mu, the mean length of bass caught in a small lake. A normal distribution was assumed. Using the 90% confidence interval obtain:

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Step-by-step explanation:

From the question we are told that

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  From the question we are told the confidence level is  95% , hence the level of significance is    

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=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

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=>    E =  1.96 *  \frac{5.932}{\sqrt{18} }

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Generally 95% confidence interval is mathematically represented as  

      \= x -E <  \mu <  \=x  +E

=>    13.4  -  2.7  <  \mu < 13.4  +   2.7

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