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3 years ago

13

At SMS, students were encouraged to wear school colors of blue and white. 900 Students wore their school colors while 300 studen

ts did not. What percent of the school population did not wear school colors?

1 answer:

emmasim [6.3K]3 years ago

4 0

Answer:300/1200

Step-by-step explanation:part/whole = %/100

300/1200 =25

/100

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To start out, notice that you want the percent of voters that chose candidate A, not the percent of the class that chose candidate A.

Your fraction should be "number that chose candidate A" out of "number of voters," which is the same thing as saying:
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1) The numerator of the fraction should be the number of votes for candidate A, which is 11.

2) The denominator of the fraction should be the number of voters. You're told that "t<span>here were 11 votes for Candidate A and 15 votes for Candidate B," so there are:
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3) Finally put parts 1 and 2 together into a fraction and multiply by 100 to get your percent. That is your final answer:
$\frac{11}{11+15} \times 100$

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Answer: Top right choice, $\frac{11}{11+15} \times 100$
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3 years ago

IMPORTANT!! in a unit circle, what is the relationship between arc length and central angle?

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Answer:

The measure of an arc refers to the arc length divided by the radius of the circle. The arc measure equals the corresponding central angle measure, in radians. That's why radians are natural: a central angle of one radian will span an arc exactly one radius long.

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3 years ago

Donna packs 14 pounds of nuts in bags . Each bag has 1/4 pound of nuts Which equation shows the number of bags Donna packed with

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Answer:

Step-by-step explanation:

Where are the equations to choose from?

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3 years ago

Look at the triangle show on the right. The Pythagorean Theorem states that the sum of the squares of the legs of a right triang

Vladimir [108]

Answer:

$cos^2\theta + sin^2\theta = 1$

Step-by-step explanation:

Given

$(\frac{b}{r})^2 + (\frac{a}{r})^2$

Required

Use the expression to prove a trigonometry identity

The given expression is not complete until it is written as:

$(\frac{b}{r})^2 + (\frac{a}{r})^2 = (\frac{r}{r})^2$

Going by the Pythagoras theorem, we can assume the following.

a = Opposite
b = Adjacent
r = Hypothenuse

So, we have:

$Sin\theta = \frac{a}{r}$

$Cos\theta = \frac{b}{r}$

Having said that:

The expression can be further simplified as:

$(\frac{b}{r})^2 + (\frac{a}{r})^2 = 1$

Substitute values for sin and cos

$(\frac{b}{r})^2 + (\frac{a}{r})^2 = 1$ becomes

$cos^2\theta + sin^2\theta = 1$

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4 years ago

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DENIUS [597]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers