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larisa86 [58]
3 years ago
13

At SMS, students were encouraged to wear school colors of blue and white. 900 Students wore their school colors while 300 studen

ts did not. What percent of the school population did not wear school colors?
Mathematics
1 answer:
emmasim [6.3K]3 years ago
4 0

Answer:300/1200

Step-by-step explanation:part/whole = %/100

300/1200 =25

/100

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She poured 2L into each.

10 / 5 = 2
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A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th
NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

A = a + (A \cap B)

In which a is the probability that he wins the first race but not the second and A \cap B is the probability that he wins both these races.

By the same logic, we have that:

B = b + (A \cap B)

The probability that he wins both races is 0.5.

This means that A \cap B = 0.5

The probability that he wins the second race is 0.6

This means that B = 0.6

B = b + (A \cap B)

0.6 = b + 0.5

b = 0.1

The probability that he wins the first race is 0.7.

This means that A = 0.6

A = a + (A \cap B)

0.7 = a + 0.5

a = 0.2

A) he wins at least one race.

This is

P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

P = a + b = 0.2 + 0.1 = 0.3

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0
3 years ago
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WINSTONCH [101]
967.50 = 450 + 28.75p
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3 years ago
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Solve the equation. 33 = p – 6.71<br> A. –39.71 <br> B. –26.29 <br> C. 39.71 <br> D. 26.29
jeka57 [31]

<u>Answer</u>

C. 39.71


<u>Explanation</u>

33 = p - 6.71

The first step is to make the like terms to be on the same side.

Add 6.71 on both sides of the eqution

33 +  6.71 = p - 6.71 + 6.71

39.71 = p


∴ p = 39.71

4 0
3 years ago
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