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xxMikexx [17]
3 years ago
14

23x +5y−2, when x=6 and y=3.

Mathematics
2 answers:
zhenek [66]3 years ago
8 0

Answer:

151

Step-by-step explanation:

Plug in 23(6)+5(3)-2

Simplify 138+15-2

Solve 153-2

151

nordsb [41]3 years ago
3 0

hdjdsbsbsbhedjdidbdhdhdvdhdhd sorry I got the wrong answet

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A cookie recipe for 5 dozen cookies calls for 4 cups of flour. How many is flour is needed to make 90 cookies
azamat
6cups of flour will be needed
5*12/4= 15
90/15=6
6 0
3 years ago
Judy is a single woman, 25 years old. Her take home pay is $2314.92/month. She also earns $48 interest per month on her savings
Leni [432]

The monthly budget plan for Judy includes all of her income and expenses, the total balance is $ 2362.92 and she spends $ 1083.

<h3>What is the monthly budget?</h3>

A monthly budget is a personal spending plan that you use to track your monthly income and costs.

The given data in the problem is;

Home pay = $2314.92/month.

Interest earned = $48 / month

House rent = $825/month

EMI of student loan =  $258/month

Total earning per month = $2314.92 +  $48

Total earning per month = $ 2362.92

Amount she spends per month = $825/month + $258

Amount she spends per month = $ 1083

Hence, the total balance will be $ 2362.92 and she spend $ 1083.

To learn more about the monthly budget refer to:

brainly.com/question/570904

#SPJ1

3 0
2 years ago
The area of square LMNO is 130 square inches. Find the length of Segment LM.
lakkis [162]

Answer:

11.401754251 or the square root of 130

Step-by-step explanation:

the length squared is the area so you have to do inverse operations and do the square root

4 0
3 years ago
Given points A(-1, -2) and B(2, 4) where AP: BP=1:2, find the locus of point P.​
koban [17]

Answer:

x^2 + 4x + y^2 +8y  =  0

Step-by-step explanation:

Given

A = (-1,-2)

B = (2,4)

AP:BP = 1 : 2

Required

The locus of P

AP:BP = 1 : 2

Express as fraction

\frac{AP}{BP} = \frac{1}{2}

Cross multiply

2AP = BP

Calculate AP and BP using the following distance formula:

d = \sqrt{(x - x_1)^2 + (y - y_1)^2}

So, we have:

2 * \sqrt{(x - -1)^2 + (y - -2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}

2 * \sqrt{(x +1)^2 + (y +2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}

Take square of both sides

4 * [(x +1)^2 + (y +2)^2] = (x - 2)^2 + (y - 4)^2

Evaluate all squares

4 * [x^2 + 2x + 1 + y^2 +4y + 4] = x^2 - 4x + 4 + y^2 - 8y + 16

Collect and evaluate like terms

4 * [x^2 + 2x + y^2 +4y + 5] = x^2 - 4x + y^2 - 8y + 20

Open brackets

4x^2 + 8x + 4y^2 +16y + 20 = x^2 - 4x + y^2 - 8y + 20

Collect like terms

4x^2 - x^2 + 8x + 4x + 4y^2 -y^2 +16y + 8y  + 20 - 20 =  0

3x^2 + 12x + 3y^2 +24y  =  0

Divide through by 3

x^2 + 4x + y^2 +8y  =  0

3 0
3 years ago
Use the discriminant to describe the roots of each equation. Then select the best description. 2 = x2 + 5x. A) Double root B) Re
fredd [130]

\bf 2=x^2+5x\implies 0=x^2+5x-2\\\\\\\qquad \qquad \qquad \textit{discriminant of a quadratic}\\\\\\0=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+5}x\stackrel{\stackrel{c}{\downarrow }}{-2}~~~~~~~~\stackrel{discriminant}{b^2-4ac}=\begin{cases}0&\textit{one solution}\\positive&\textit{two solutions}\\negative&\textit{no solution}\end{cases}\\\\\\(5)^2-4(1)(-2)\implies 25+8\implies 33


so we have a 33, namely two real solutions for that quadratic.


usually that number goes into a √, if you have covered the quadratic formula, you'd see it there, namely that'd be equivalent to √(33), now 33 is a prime number, and √(33) is yields an irrational value, specifically because a prime number is indivisible other than by itself or 1.


so 33 can only afford us two real irrational roots.

3 0
3 years ago
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