The rational numbers are the positive counting numbers: 1, 2, 3, 4, . . .
The whole number are the natural numbers plus 0: 0, 1, 2, 3, . . .
The irrational numbers are the numbers which cannot be expressed in the form a/b where a and b are integers. They are usually in the form of a non recurring and non terminating decimals.
The integers complices of both the negative and the positive whole numbers.
In winter, the temperature of Alaska usually drop to negative numbers.
Therefore, the <span>set of numbers is the most reasonable to describe the temperature in alaska during the winter is the set of integers.</span>
Answer:
no
Step-by-step explanation:
using the Factor theorem.
If (x + h) is a factor of f(x) then f(- h) = 0
for factor (x + 3) then evaluate P(- 3)
P(- 3) = (- 3)³ - 5(- 3)² + 3(- 3) + 9 = - 27 - 45 - 9 + 9 = - 72
since f(- 3) ≠ 0 then (x + 3) is not a factor of P(x)
Answer:
Honey I don't see nothing:)
Yeah sure! Just make sure to post them haha :)
Hello,
x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)
Let's use Horner's division
.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3
The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3
Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0
And here, Mehek are there sufficients explanations?