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3 years ago

In the diagram shown at left, three lines intersect to form a triangle. What is the value of x?

Mathematics

1 answer:

Phoenix [80]3 years ago

5 0

Answer:

39°

Step-by-step explanation:

For a straight line, the sum of angle is 180°

At the point where we have the 107°, the inner angle in the triangle will be 180-107=73°

68° is alternate angle to the inner angle in the triangle

Since the sum of angles in a triangle are 180°, then angle x will be

X=180-73-68=39°

Therefore, missing angle is 39°

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Ulleksa [173]

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3 years ago

What is the slope of the line given by the equation y-9=15(x-5) ?

Alexxx [7]

The final equation after distributing is:

y = 15x - 66

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3 years ago

Can someone answer this question as a proper number with all the calculations<br> (5)20*(4)13

Slav-nsk [51]

Hello! So our final answer is 5,200.. Let me show you how I got it!

It's actually quite simple. I broke it into smaller equations..

Step One: 5 * 20 = 100

Step Two: 4 * 13 = 52

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Hope this helped! Let me know if you have any further questions.

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3 years ago

Use Newton's method to find the second and third approximation of a root of x3+x+2=0 starting with x1=−1 as the initial approxim

adoni [48]

Answer:

The third approximation is $x_3=-1.08259$

Step-by-step explanation:

We are given that

$f(x)=x^3+x+2=0$

$x_1=-2$

We have to find the second and third approximation of a root of given equation by using Newton's method.

We know that Newton's method , if nth approximation is given $x_n$ and $f'(x_n)\neq 0$ then, the next approximation is given by

$x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}$

$f'(x)=3x^2+1$

Substitute $x_1=-2$

$f(x_1)=f(-2)=(-2)^3+(-2)+2=-8$

$f'(x_1)=f'(-2)=3(-2)^2+1=13$

Substitute the value n=1 then, we get

$x_2=x_1-\frac{f(x_1)}{f'(x_1)}$

Substitute the values then , we get the second approximation

$x_2=-2-\frac{-8}{13}=-\frac{18}{13}$

For n=2

$f(x_2)=f(-\frac{18}{13})=(-\frac{18}{13})^3-\frac{18}{13}+2=-2.03914$

$f'(x_2)=f'(-\frac{18}{13})=3(-\frac{18}{13})^2+1=6.75148$

$x_3=x_2-\frac{f(x_2)}{f'(x_2)}$

$x_3=-\frac{18}{13}-\frac{-2.03914}{6.75148}=-1.08259$

Hence, the third approximation is $x_3=-1.08259$

7 0

3 years ago

Round 1.802 to 1 significant figure

DanielleElmas [232]

Answer : I believe it is 4

4 0

2 years ago