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4 years ago

Given: x + 2 < -5.

Mathematics

2 answers:

hammer [34]4 years ago

7 0

Answer:

A. {x/x R, x< -7}

Step-by-step explanation:

x+ 2 < -5 becames x < -7 by subtracting -2 at both sides of the inequation. Because inequations mantain the same direction when the operation of sum or subtraction is applied, the results yiels x< -7-

mr_godi [17]4 years ago

5 0

Answer:

Choice A. { $x|x\,\epsilon\,R, x\,$ }

Step-by-step explanation:

Start by working on isolating the variable "x" in the inequality $x+2$ . We can do such by subtracting "2" from both sides:

$x+2$

Therefore, we need to consider all those real values of the variable "x" which are strictly smaller than -7 (reside to the left of -7 on the number line).

Such set of x-values can be described in set notation (the notation suggested in your answer choices) specifying:

a) with the group symbols "{" and "}" the beginning and the end respectively of the set to be described,

b) with the expression "x |" we state: all those x-values such that,

c) with the symbols $x\,\epsilon\,R$ we state: x belongs to the set of Real (R) numbers,

d) and finally the condition on the values allowed for the variable x: x < -7 (x values must be strictly smaller than "-7"

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Help please

Vadim26 [7]

✡ Answer: 75; 100-25-5 ✡

- - To solve this you are going to subtract.
Because you are taking away apples, in this case eating them

- - So: 100-20-5

Answer: 75

✡Hope this helps!✡

7 0

3 years ago

Read 2 more answers

|x+10| / 9 < 2 Solve the inequality, show step by step

Lerok [7]

Answer:x=8

Step-by-step explanation:

3 0

3 years ago

Find x, y, and z such that x³+y³+z³=k, for each k from 1 to 100.

love history [14]

Answer:

x3+y3+z3=k with k is integer from 1 to 100

solution x=0 , y=0 and z=1 and k= 1

For K= 1 , we have the following solutions (x,y,x) = (1,0,0) ; or (0,1,0) ; or (0,0,1) ,

For k =1 also (9,-8,-6) or (9,-6,-8) or (-8,-6,9) or (-8,9,-6) or (-6,-8,9) or (-6,9,8)

And (-1,1,1) or (1,-1,1)

=>(x+y)3−3x2−3xy2+z3=k

=>(x+y+z)3−3(x+y)2.z−3(x+y).z2=k

=>(x+y+z)3−3(x+y)z[(x+y)−3z]=k

lety=αand z=β

=>x3=−α3−β3+k

For k= 2 we have (x,y,z) = (1,1,0) or (1,0,1) or (0,1,1)

Also for (x,y,z) = (7,-6,-5) or (7,-6,-5) or (-6,-5,7) or (-6,7,-5) or (-5,-6,7) or (-5,7,-6)

For k= 3 we have 1 solution : (x,y,z) = (1,1,1)

For k= 10 , we have the solutions (x,y,z) = (1,1,2) or (1,2,1) or (2,1,1)

For k= 9 we have the solutions (x,y,z) = (1,0,2) or (1,2,0) or (0,1,2) or (0,2,1) or (2,0,1) or (2,1,0)

For k= 8 we have (x,y,z) = ( 0,0,2) or (2,0,0) or (0,2,0)

For k= 17 => (x,y,z) = (1,2,2) or (2,1,2) or ( 2,2,1)

For k = 24 we have (x,y,z) = (2,2,2)

For k= 27 => (x,y,z) = (0,0,3) or (3,0,0) or (0,3,0)

for k= 28 => (x,y,z) = (1,0,3) or (1,3,0) or (1,3,0) or (1,0,3) or (3,0,1) or (3,1,0)

For k=29 => (x,y,z) = (1,1,3) or (1,3,1) or (3,1,1)

For k = 35 we have (x,y,z) = (0,2,3) or (0,3,2) or (3,0,2) or (3,2,0) or 2,0,3) or (2,3,0)

For k =36

we have also solution : x=1,y=2andz=3=>

13+23+33=1+8+27=36 with k= 36 , we have the following

we Have : (x, y,z) = (1, 2, 3) ; (3,2,1); (1,3,2) ; (2,1,3) ; (2,3,1), and (3,1,2)

For k= 43 we have (x,y,z) = (2,2,3) or (2,3,2) or (3,2,2)

For k = 44 we have ( 8,-7,-5) or (8,-5,-7) or (-5,-7,8) or ( -5,8,-7) or (-7,-5,8) or (-7,8,-5)

For k =54 => (x,y,z) = (13,-11,-7) ,

for k = 55 => (x,y,z) = (1,3,3) or (3,1,3) or (3,1,1)

and (x,y,z) = (10,-9,-6) or (10,-6,-9) or ( -6,10,-9) or (-6,-9,10) or (-9,10,-6) or (-9,-6,10)

For k = 62 => (x,y,z) = (3,3,2) or (2,3,3) or (3,2,3)

For k =64 => (x,y,z) = (0,0,4) or (0,4,0) or (4,0,0)

For k= 65 => (x,y,z) = (1,0,4) or (1,4,0) or (0,1,4) or (0,4,1) or (4,1,0) or (4,0,1)

For k= 66 => (x,y,z) = (1,1,4) or (1,4,1) or (4,1,1)

For k = 73 => (x,y,z) = (1,2,4) or (1,4,2) or (2,1,4) or (2,4,1) or (4,1,2) or (4,2,1)

For k= 80=> (x,y,z)= (2,2,4) or (2,4,2) or (4,2,2)

For k = 81 => (x,y,z) = (3,3,3)

For k = 90 => (x,y,z) = (11,-9,-6) or (11,-6,-9) or (-9,11,-6) or (-9,-6,11) or (-6,-9,11) or (-6,11,-9)

k = 99 => (x,y,z) = (4,3,2) or (4,2,3) or (2,3,4) or (2,4,3) or ( 3,2,4 ) or (3,4,2)

(x,y,z) = (5,-3,1) or (5,1,-3) or (-3,5,1) or (-3,1,5) or (1,-3,5) or (1,5,-3)

=> 5^3 + (-3)^3 +1 = 125 -27 +1 = 99 => for k = 99

For K = 92

6^3 + (-5)^3 +1 = 216 -125 +1 = 92

8^3 +(-7)^3

Step-by-step explanation:

4 0

3 years ago

Consider this expression:

Tema [17]

8(4a+2b)
The equivalent is 32a+16b (B)

4 0

3 years ago

Listed below are several statements that relate to financial accounting and reporting. Identify the accounting concept that appl

9966 [12]

Answer:

The accounting concept that applies to the given statements is as follow:

1. SiriusXM Radio Inc. files its annual and quarterly financial statements with the SEC. ⇒ The Periodicity Assumption.

2. The president of Applebee’s International, Inc., travels on the corporate jet for business purposes only and does not use the jet for personal use. ⇒ The Economic Entity Assumption.

3. Jackson Manufacturing does not recognize revenue for unshipped merchandise even though the merchandise has been manufactured according to customer specifications. ⇒ Revenue Recognition

4. Lady Jane Cosmetics depreciates the cost of equipment over their useful lives. ⇒ Expense Recognition

6 0

4 years ago