
The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

RADIUS = 2
CHORD = 2
RADIUS --> XY , XZ , WX
( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

AREA COVERED BY THE ANGLE IN A SEMI SPHERE


Total Area Of The Semi Sphere:-

Area Under Unshaded Part .
Given a triangle with each side 2 units.
This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian
So AREA :-


Total Area - Area Under Unshaded Part


Cot(3x)=3^(1/2)
cot(x)= cos(x)/sin(x)
cot(3x)= cos(3x)/sin(3x)
look at a unit circle chart
find a value for cos that has sqrt(3) in it
which one will reduce so that the cos/sin will equal sqrt(3)?
pi/6 radians
now cot(3x) implies that x is one third this value
pi/18 is the answer
Answer:
Step-by-step explanation:
5y + 6y + 7y = 18y......any numbers that add(or subtract) to equal 18, stick them before the y....
or it could be : 10y + 10y - 2y = 18y or 5y + 10y + 3y or 30y - 20y + 8y....I could go on forever...lol
Answer:
Murat can fill 6/13 kg of rice
Step-by-step explanation:
because it has 2/3 kg of rice and 3/10 each and I added 6+2 and 3+10 hope it makes your day
Answer:
[(a)^2-(4^2)](a+4)
Step-by-step explanation: