Basically you are trying to find two numbers that when they are added equals -2 and when multiplied equals -3. As you can see -3 plus +1 is equal to -2. And 1 times -3 equals -3. Therefore you have (x+1)(x-3). In order to check if these are the right numbers you will need to multiply (x+1)(x-3) and will end up with the first equation x^2-2x-3. Hope this helped! :)
Answer:
22/40 or 11/20
Step-by-step explanation:
12 + 10 + 18 = 40
12+ 10 = 22
Answer:
Step-by-step explanation:
3x+4y=−23.........(1)
x=3y+1 .........(2)
Putting (2) in (1)
3(3y + 1) + 4y = -23
9y + 3 + 4y = -23
9y + 4y = -23 - 3
13y = -26
y = -26/13
y = -2
Putting y into (2)
x=3y+1
x = 3(-2) + 1
x = -6 + 1
x = -5
Answer:
dx/dy = (x^4 - 2x^5y - 6xy^2) / (5x^4y^2 - 4x^3y + 2y^3).
Step-by-step explanation:
x^5y^2 − x^4y + 2xy^3 = 0
Applying the Product and Chain Rules:
y^2*5x^4*dx/dy + 2y*x^5 - (y*4x^3*dx/dy + x^4) + (y^3* 2*dx/dy + 3y^2*2x) =0
Separating the terms with derivatives:
y^2*5x^4*dx/dy - y*4x^3*dx/dy + y^3* 2*dx/dy = x^4 - 2y*x^5 - 3y^2*2x
dx/dy = (x^4 - 2x^5y - 6xy^2) / (5x^4y^2 - 4x^3y + 2y^3)
Answer:
Step-by-step explanation:
