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MrMuchimi
3 years ago
13

Composition of functions Find g (f(x)) for the following problems

Mathematics
1 answer:
beks73 [17]3 years ago
7 0

1.

f(x)=-3x\qquad g(x)=5x-6\\\\g(f(x))=5(-3x)-6=\boxed{-15x-6}

2.

f(x)=x-6\qquad g(x)=x^2+6x-2\\\\g(f(x))=(x-6)^2+6(x-6)-2=x^2-12x+36+6x-36-2=\\\\=\boxed{x^2-6x-2}

3.

f(x)=4x+3\qquad g(x)=2x^2-x+1\\\\g(f(x))=2(4x+3)^2-(4x+3)+1=2(16x^2+24x+9)-4x-3+1=\\\\=32x^2+48x+18-4x-3+1=\boxed{32x^2+44x+16}

4.

f(x)=2x^2\qquad g(x)=8x^2+3x\\\\g(f(x))=8(2x^2)^2+3(2x^2)=8\cdot4x^4+6x^2=\boxed{32x^4+6x^2}

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Fernando has some nickels, dimes, and quarters that are worth a total of $3.25. He has twice as many dimes as nickels. He has 3
CaHeK987 [17]

Answer:

Number of nickels = 5

Number of dimes = 10

Number of quarters = 8

Step-by-step explanation:

Fernando has a total of nickels + dimes + quarters = 3.25$

Let the number of nickels = x

Then x(.05) + dimes(.10) + quarters(0.25) = 3.25------(1)

He has twice as many dimes as nickels

dimes = 2×nickels

dimes = 2x--------(2)

He has 3 more quarters than nickels

quarters = nickels +3

quarters = x +3------(3)

From equations 1, 2, and 3.

x(.05) + 2x(.10) + (x + 3)(.25) = 3.25

.05x + 0.2x + 0.25x + .75 = 3.25

5x + 20x + 25x + 75 = 325

50x = 325 - 75

50x = 250

x = 5

Therefore the number of nickels are 5

from equation 2 number of dimes are 10

and from equation 3 number of quarters are 8.

3 0
3 years ago
Find the difference 3/4 - 5/8.
seraphim [82]

-Hello There-

If We Subtracted 5/8 From 3/4 We Would Have A Difference Of <u><em>1/8</em></u>

<u><em></em></u>

<u><em>Have A Great Day!</em></u>

4 0
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GalinKa [24]

Answer:

3 9/50

Step-by-step explanation:

3.18 is 3 18/100

Simplifying it further you get: 3 9/50

4 0
3 years ago
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Find the number of real number solutions for the equation. x2 + 0x − 1 = 0
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Answer:

x=1 or x=−1 its either one of the other.

Step-by-step explanation:

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3 years ago
B to the power of 3 =343
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Answer:

Step-by-step explanation:

B³=343

or

B³=7³

B=7

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