first 1/8 then 4/8 and lastly 7/8
Answer:
Green
Step-by-step explanation:
The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
To learn more about the solution visit:
brainly.com/question/1397278
Answer:
C).
Step-by-step explanation:
-3x+2 and[(-)(x^2+5x)
3x+2 and (-x^2+5x)
3x+2-x^2+5x
-x^2-8x+2
Hope this Helps :)
