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yuradex [85]
3 years ago
9

Find the modulus of the following |9+40i|

Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

modulus of  |9+40i|  is 41

Step-by-step explanation:

Let z = 9+40i

then

|z| = \sqrt{9^{2}+40^{2}  }

   = \sqrt{81+1600}

   = \sqrt{1681}

   = 41

|z| = 41

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