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yuradex [85]
3 years ago
9

Find the modulus of the following |9+40i|

Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

modulus of  |9+40i|  is 41

Step-by-step explanation:

Let z = 9+40i

then

|z| = \sqrt{9^{2}+40^{2}  }

   = \sqrt{81+1600}

   = \sqrt{1681}

   = 41

|z| = 41

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Question in image. :)
quester [9]

a. f(a) =5a+12

we have 1. a=6

Therefore, where ever we find a we'll substitute in 6

f(6) =5(6) +12

6f=30+12

6f=42

so therefore 1. a=6 will match c on the right

2. a=2

f(2) =5(2) +12

2f = 10+12

2f = 22

therefore 2. a=2 will match a on the right

3. a=4

f(4) =5(4) +12

4f=20+12

4f=32

therefore 3. a=4 will match d on the right

4. a=5

f(5) =5(5) +12

5f=25+12

5f=37

therefore 4. a=5 will match b on the right

7 0
2 years ago
Answer questions a) and b)
Mariulka [41]

Answer:

x\hookrightarrow -1\hookrightarrow 0\hookrightarrow 1\hookrightarrow 2\hookrightarrow 3\hookrightarrow 4\hookrightarrow 5

y\hookrightarrow 5\hookrightarrow 0\hookrightarrow -3\hookrightarrow -4\hookrightarrow -3\hookrightarrow 0\hookrightarrow 5

The curve (B) matches the graph of y=x²-4x.

----------\\Hope \ it\;helps

4 0
3 years ago
Help please! find m∠bcf
77julia77 [94]

Answer:

BCF = 140°

See attached image.

5 0
2 years ago
Read 2 more answers
In circle O, AC and BD are diameters.
Ronch [10]

Answer:

mArc A B = 120° (C)

Step-by-step explanation:

Question:

In circle O, AC and BD are diameters.

Circle O is shown. Line segments B D and A C are diameters. A radius is drawn to cut angle D O C into 2 equal angle measures of x. Angles A O D and B O C also have angle measure x.

What is mArc A B?

a)72°

b) 108°

c) 120°

d) 144°

Solution:

Find attached the diagram of the question.

Let P be the radius drawn to cut angle D O C into 2 equal angle measures of x

From the diagram,

m Arc AOC = 180° (sum of angle in a semicircle)

∠AOD + ∠DOP + ∠COP = 180° (sum of angles on a straight line)

x° +x° + x° =180°

3x = 180

x = 180/3

x = 60°

m Arc DOB = 180° (sum of angle in a semicircle)

∠AOB + ∠AOD = 180° (sum of angles on a straight line)

∠AOB + x° = 180

∠AOB + 60° = 180°

∠AOB = 180°-60°

∠AOB = 120°

mArc A B = 120°

5 0
2 years ago
Solve 5-3^x=-40 round to the nearest ten-thousandth
solong [7]

5-3^x = -40

 subtract 5 from each side to get

-3^x=-45

 divide both sides by -1 to make them positive

3^x = 45

need to do the natural logarithm on both sides to remove the variable from the exponent

 so ln(3^x) = ln(45)

 use logarithm rule to move x out

x ln (3) = ln(45)

 dive each term by ln(3) then simplify to get

ln(3)/ln(45)

 so x = ln(3)/ln(45) which calculates out to 3.46497352

round off to ten thousandths is 3.4650

 

4 0
3 years ago
Read 2 more answers
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