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3 years ago

How do I round it if technically it’s already to the nearest hundredth

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

7 0

Leave the answer how it is

I hope this helps

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310=-6.2f solve for f

Naddik [55]

Divide both sides by -6.2:
-50 = f

6 0

3 years ago

Find the limit

Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

$\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}$

$\rm \: = \sf \: \: - \infty \: - \: \infty$

which is indeterminant form.

Consider again,

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

can be rewritten as

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]$

$\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}$

$\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}$

$\rm \: = \: \sf \boxed{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}$

$\rule{190pt}{2pt}$

7 0

2 years ago

Read 2 more answers

The sum of the present ages of the mother and her daughter is 80 years. The mother was thrice as old as her daughter when she wa

Alika [10]

Answer:

let the daughter age be x

let mother age be 3x

Step-by-step explanation:

x+3x= 80

4x = 80

x= 80\4

x=20

daughter age is 20

mather age= 80 -20

= 60

daughter age 20

mother age 60

7 0

3 years ago

If eleven plus two equal one,what dose nine plus five equal? <br>and one more <br>

Rama09 [41]

Answer:

2 O'Clock

Step-by-step explanation:

If 11+2=1

We want to determine what the value of 9+5 is.

11 O'Clock+2 Hours =1 O'Clock

Therefore:

9 O'Clock + 5 Hours =2 O'Clock

6 0

3 years ago

Read 2 more answers

Four consecutive odd integers add up to -48. What is the least of these integers?

Semmy [17]

Answer:

-9

Step-by-step explanation:

Four consecutive odd integers be (2x - 3),(2x -1),(2x + 1),(2x + 3)

2x-3 + 2x - 1 +2x+1 + 2x+3 = -48

2x + 2x + 2x +2x - 3 - 1 + 3 + 1 = -48

8x = -48

x = -48/8

x = -6

Least of these integer = 2x + 3 = 2*(-6) + 3 = -12 + 3 = -9

3 0

3 years ago