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Naya [18.7K]
4 years ago
8

6+(w-10)=5 solve for w

Mathematics
1 answer:
andreyandreev [35.5K]4 years ago
6 0

Answer:

w = 9

Step-by-step explanation:

9-10 = -1

6+-1 = 5.

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Solve the system of equations.<br> 2x + 7y = 3<br> x= -4y
I am Lyosha [343]

Answer:

(12, -3)

Step-by-step explanation:

You can solve it algebraically or graphically. Graphically you find the intersection point. Algebraically with substitution/elimination.

5 0
3 years ago
1. Charlene wants to center a rectangular pool in her backyard so that the edges of the pool are an equal distance from the edge
Inga [223]

First, we have to calculate the length of the sides of the pool, we are told that the scale factor of the backyard to the pool size equals 1/2, then we can find the length of the sides of the pool by multiplying the lengths of the sides of the backyard by 1/2, like this:

length of the pool = length of the yard * 1/2

width of the pool = width of the yard * 1/2

By replacing the 60 m for the length of the yard and 50 m for the width, we get:

length of the pool = 60 * 1/2 = 30

width of the pool = 50 * 1/2 = 25

Let's call x1 to the distance from the base of the pool to the bottom side of the yard and x2 to the distance from the top side of the pool to the top side of the yard, then we can formulate the following equation:

width of the yard = width of the pool + x1 + x2

Since we want the edges to be at an equal distance, x1 and x2 are the same, then we can rewrite them as x:

width of the yard = width of the pool + x + x

width of the yard = width of the pool + 2x

Replacing the known values:

60 = 30 + 2x

From this equation, we can solve for x to get:

60 - 30 = 30 - 30 + 2x

30 = 2x

30/2 = 2x/2

15 = x

x = 15

Now, let's call y1 to the distance from the right side of the corresponding side of the yard and y2 to the distance from the left side of the pool to the left side of the yard, with this, we can formulate the following equation:

length of the yard = length of the pool + y1 + y2

Since we want the edges to be at an equal distance, y1 and y2 are the same, then we can rewrite them as y:

length of the yard = length of the pool + y + y

length of the yard = length of the pool + 2y

Replacing the known values:

50 = 25 + 2y

50 - 25 = 25 - 25 + 2y

25 = 2y

25/2 = 2y/2

12.5 = y

y = 12.5

Now, we know that the pool must be at a distance of 15 m from the horizontal sides of the pool to the horizontal sides of the yard and that it must be at a distance of 12.5 m from the vertical sides of the pool to the vertical sides of the yards.

Here is a figure that depicts the results:

5 0
1 year ago
1. SOLVE THE EQUATION BELOW
Gemiola [76]

Answer:

 D     F/a =m  Mrs  Kaulter

Step-by-step explanation:

F = ma

Divide each side by a

F/a = ma/a

F/a =m

5 0
3 years ago
How to find mean, variance and standard deviation of each data set of 4,6,7,7,5,1,2,3
Sholpan [36]

Answer:

search it up

Step-by-step explanation:

add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

8 0
3 years ago
50 POINTS please help me I really need it
Mars2501 [29]

A Domain is the lowest and highest x value (-5,-2) is how it is formatted this means -5 to -2

Range is the lowest to highest Y value so (-3,3)

(-5,-2) - domain

(-3,3) - range

B Intercept are when the line crosses the acis labeled x so

(-2,0) and (2,0)

C F(1) means what is x when y is equal to 1 so we must estimate this

(-1,1) and (1.5,1)

D f(x) = -3 is when y is -3 so we look at the graph to see

-5 and 4 are the values for x

E f(x) < 0 means when y is above the x axis

This is between the x values of -2 and 2 or (-2,2)


7 0
4 years ago
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