From my work I believe it should be the third one.
Answer:
A = 20sinθ(6 + 5 cosθ) cm²
Step-by-step explanation:
Drop perpendiculars DE and CF to AB.
Then, we have congruent triangles ADE and BCF, plus the rectangle CDEF.
The formula for the area of the trapezium is
A = ½(a + b)h
DE = 10sinθ
AE = 10cosθ
BF = 10cosθ
EF = CD = 12 cm
AB = AE + EF + BF = 10cosθ + 12 + 10 cosθ = 12 + 20cosθ
A = ½(a + b)h
= ½(12 +12 + 20 cosθ) × 10 sinθ
=(24 + 20 cosθ) × 5 sinθ
= 4(6 + 5cosθ) × 5sinθ
= 20sinθ(6 + 5 cosθ) cm²
Answer:
His gain percent is 20%
Step-by-step explanation:
In this question, we want to find the percentage gain of the business.
We need the following parameters;
The cost price which is the sum of the amount she bought the goods + the amount spent on transport
Using the values we have in the question;
The cost price will be;
13,600 + 400 = Rs 14,000
The selling price = Rs 16,800
Mathematically the percentage gain will be;
% gain = (selling price- cost price)/selling price * 100%
% gain = (16,800-14,000)/14,000 * 100/1
% gain = 2800/14,000 * 100/1 = 1/5 * 100/1 = 20%
The answer is 2/3 because 3/8x16/9= 2/3
| 42 | The absolute value of forty two