What exactly is your question?? If you are driving all pedestrians have the right way.....treat all intersections as a crosswalk painted or not!!!
Explanation:
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Answer:
A real-time operating system is an operating system designed to support real-time applications that, usually without buffer delays, process data as it comes in. A real-time system is a time-bound system that has fixed, well defined time constraints.
Answer:
Following is the algorithm to interchange the value of two variable x and y.
step 1:Read the two integer x and y.
step 2 :t=x
Step 3: x=y
step 4: y=t
The minimum number of assignment to do this is 3
Explanation:
After reading two integer x & y, create a variable "t" of integer type.
with the help of variable "t", we can swap the value of variable x and y.
It requires 3 assignment to interchange the value.
Answer:
% here x and y is given which we can take as
x = 2:2:10;
y = 2:2:10;
% creating a matrix of the points
point_matrix = [x;y];
% center point of rotation which is 2,2 here
x_center_pt = x(2);
y_center_pt = y(2);
% creating a matrix of the center point
center_matrix = repmat([x_center_pt; y_center_pt], 1, length(x));
% rotation matrix with rotation degree which is 45 degree
rot_degree = pi/4;
Rotate_matrix = [cos(rot_degree) -sin(rot_degree); sin(rot_degree) cos(rot_degree)];
% shifting points for the center of rotation to be at the origin
new_matrix = point_matrix - center_matrix;
% appling rotation
new_matrix1 = Rotate_matrix*new_matrix;
Explanation:
We start the program by taking vector of the point given to us and create a matrix by adding a scaler to each units with repmat at te center point which is (2,2). Then we find the rotation matrix by taking the roatational degree which is 45 given to us. After that we shift the points to the origin and then apply rotation ans store it in a new matrix called new_matrix1.
