num1 = float(input("Enter the first number: "))
num2 = float(input("Enter the second number: "))
if num1 > num2:
print(num1)
else:
print(num2)
I hope this helps!
Answer:
Corrective Control
Explanation:
Physical Control are devices that limit access or otherwise protect a resource, such as fences, doors, locks and fire extinguishers.
Technical Control are devices or processes that limit access to resources. Examples include user authentication, antivirus software, and firewalls. Technical controls are also called <em>Logical Control</em>
Corrective Control repair the effects of damage from an attack. Corrective contol include: include virus removal procedures, firewall table updates, and user authorisation database updates.
These are the functions that return a value after their completion. A fruitful function must always return a value to where it is called from. A fruitful function can return any type of value may it be string, integer, boolean, etc. It is not necessary for a fruitful function to return the value of one variable, the value to be returned can be an array or a vector. A fruitful function can also return multiple values.
A Network Switch and Network Hub are similar computer network components that connect multiple devices in a computer network. A Network switch is used to connect various network segments. It is a small hardware device that joins multiple computers together within one local area network (LAN). A Network Hub connects numerous Ethernet devices together, making them act as a single segment.
Answer:
Hi, for this exercise we have two laws to bear in mind:
Morgan's laws
NOT(А).NOT(В) = NOT(A) + NOT (B)
NOT(A) + NOT (B) = NOT(А).NOT(В)
And the table of the Nand
INPUT OUTPUT
A B A NAND B
0 0 1
0 1 1
1 0 1
1 1 0
Let's start!
a.
Input OUTPUT
A A A NAND A
1 1 0
0 0 1
b.
Input OUTPUT
A B (A NAND B ) NAND (A NAND B )
0 0 0
0 1 0
1 0 0
1 1 1
C.
Input OUTPUT
A B (A NAND A ) NAND (B NAND B )
0 0 0
0 1 1
1 0 1
1 1 1
Explanation:
In the first one, we only need one input in this case A and comparing with the truth table we have the not gate
In the second case, we have to negate the AND an as we know how to build a not, we only have to make a nand in the two inputs (A, B) and the make another nand with that output.
In the third case we have that the OR is A + B and we know in base of the morgan's law that:
A + B = NOT(NOT(А).NOT(В))
So, we have to negate the two inputs and after make nand with the two inputs negated.
I hope it's help you.
