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cluponka [151]
3 years ago
11

How would you get y by it's self​

Mathematics
2 answers:
loris [4]3 years ago
5 0

Answer:

In what problem?

Step-by-step explanation:

Simora [160]3 years ago
3 0
Um I would have to see the full problem to say the answer
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HELP ME ON THIS PLEASE!!!! SHOW WORK!!!!
Mumz [18]

Answer:

<h2>1. x = 4</h2><h2>2. x = 20</h2>

Step-by-step explanation:

1.

ΔABC and ΔAJK are similar (AA). Therefore the sides are in proportion:

\dfrac{AC}{AJ}=\dfrac{AB}{AK}

We have:

AC = 1 + 4 = 5

AJ = 1

AB = 1 + x

AK = 1

Substitute:

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5=1+x           <em>subtract 1 from both sides</em>

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2.

ΔVUT and ΔVMN are similar (AA). Therefore the sides are in proportion:

\dfrac{VU}{VM}=\dfrac{VT}{VN}

We hve:

VU = x + 8

VM = x

VT = 49

VN = 49 - 14 = 35

Substitute:

\dfrac{x+8}{x}=\dfrac{49}{35}              <em>cross multiply</em>

35(x+8)=49x          <em>use the distributive property a(c + b) = ab + ac</em>

35x+280=49x              <em>subtract 35x from both sides</em>

280=14x         <em>divide both sides by 14</em>

20=x\to x=20

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