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tatuchka [14]
3 years ago
5

Which measurement is most accurate to describe the weight of a baby

Mathematics
2 answers:
artcher [175]3 years ago
5 0

Answer:

Option 4). 4.5 kg

Step-by-step explanation:

The given options for the weight of a baby are

1) 5000 mg = 5000/1000 gms = 5 gms = .005 kg

2) 1400 g = 1.5 kg

3) 350 mg = 0.35 gms = 0.35(10^{-3}) kg

4) 4.5 kg

Out of these options option 4 is the most suitable weight that describes the weight of a baby.

Lapatulllka [165]3 years ago
5 0
<h2>Answer:</h2>

<u>The right choice is </u><u>(D) 4.5 kg</u>

<h2>Step-by-step explanation:</h2>

If we look at the choices given above

5000 mg = 0.005kg which is not possible for the weight of a baby.

Similarly 1400 kg equals 1.4 kg which also doesn't make sense. In the same way 350 mg is also very less value for the weight of a baby so the only option that is suitable is 4.5kg which is option D

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Two different simple random samples are drawn from two different populations. The first sample consists of 30 people with 16 hav
Furkat [3]

Answer:

  • There is no significant evidence that p1 is different than p2 at 0.01 significance level.
  • 99% confidence interval for p1-p2 is  -0.171 ±0.237 that is (−0.408, 0.066)

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

H_{0}: p1-p2=0

H_{a}: p1-p2≠0

Test statistic can be found using the equation:

z=\frac{p2-p1}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of the common attribute in population1 (\frac{16}{30} =0.533)
  • p2 is the sample proportion of the common attribute in population2 (\frac{1337}{1900} =0.704)
  • p is the pool proportion of p1 and p2 (\frac{16+1337}{30+1900}=0.701)
  • n1 is the sample size of the people from population1 (30)
  • n2 is the sample size of the people from population2 (1900)

Then z=\frac{0.704-0.533}{\sqrt{{0.701*0.299*(\frac{1}{30} +\frac{1}{1900}) }}} ≈ 2.03

p-value of the test statistic is  0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2±z*\sqrt{\frac{p1*(1-p1)}{n1}+\frac{p2*(1-p2)}{n2}} where

  • z is the z-statistic for the 99% confidence (2.58)

Thus 99% confidence interval is

0.533-0.704±2.58*\sqrt{\frac{0.533*0.467}{30}+\frac{0.704*0.296}{1900}} ≈ -0.171 ±0.237 that is (−0.408, 0.066)

7 0
3 years ago
What is the range in interval notation of the function graphed below?
attashe74 [19]

Answer:

Range tells you how high and low the graph of this parabola goes in the “y” (vertical) directions.

1. We can see that the parabola peaks on the y-axis at y = 4. That’s as HIGH as it goes.

2. We also see that both sides of the parabola descend to the level of y = -7. That’s as LOW as it is shown to go.

So putting these together, we say the Range is given by:

-7 <= y <= 3

AMBIGUITY WARNING:

Because the two branches of the parabola go fall right down to the edge of the picture boundary, it’s UNCLEAR whether the parabola truly stops at y = -7 or CONTINUES on (to negative infinity).

In THAT case, the RANGE simplifies to:

Y <= 4

Done.

Step-by-step explanation:

5 0
1 year ago
HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
lozanna [386]

Answer:

Answer in explanation

Step-by-step explanation:

Before this we do this question let's get fimiliar with what's a function.

A function is a equation that when graphed, each input(x) correspond to one output(y). This means one inputs can't map to the diffrent output.

The vertical line test is just puting a vertical line anywhere on the function. If the vertical line touches more than two points your graph is not a function. If it touches one you graph is a function. The reason is because a vertical line that touches 2 points means one x maps to two diffrent y and thats not a function.

In conclusion the graph does pass the vertical line test so it is a function.

Hope this helped!,

JoeLouis2

8 0
3 years ago
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liubo4ka [24]
The ancer is 3 i worked it out

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The answer is A. when you compress horizontally you take it by a factor of 1/a. in this case a=5. 12 is your k value and k decides whether or not you shift up or down, because k is positive or is upward by 12
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