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In-s [12.5K]
3 years ago
6

What statements apply?

Mathematics
1 answer:
IgorLugansk [536]3 years ago
6 0

Life

Hope this helps! ^-^

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A "child has six blocks, three of which are red and three of which are green". How many patterns can shemake by placing them all
makvit [3.9K]

Answer: There are 20 ways and 1680 ways respectively.

Step-by-step explanation:

Since we have given that

Total number of blocks = 6

Number of red blocks = 3

Number of green blocks = 3

So, Number of patterns she can make by placing them all in a line is given by

\dfrac{6!}{3!\times 3!}\\\\=20

If there are 3 white blocks

so, total number of white blocks becomes 9

So, Number of total pattern she can make by placing all nine blocks in a line is given by

\dfrac{9!}{3!\times 3!\times 3!}\\\\=1680\ ways

Hence, there are 20 ways and 1680 ways respectively.

6 0
3 years ago
On January 22 in 1943, the town of Spearfish, South Dakota, set the record for the world’s fastest temperature change.
Galina-37 [17]

Answer:

-29

I got this by doing:

-4 + 54 = -58 ÷ 2 = -29

3 0
2 years ago
Read 2 more answers
Given the system below, which points are solutions? (check all that apply)
LuckyWell [14K]
It’s 3.46 and 6.64hrhss
7 0
3 years ago
Conner and Jana are multiplying (3568)(39610). Conner's Work Jana's Work (3568)(39610) = 35 + 968 + 10 = 314618 (3568)(39610) =
Mariana [72]

Answer:

Neither of them has partitioned the values correctly. The answer to the sum 3568 × 39610 =141 328 480.

They tried the partition method but did not partitioned it correctly.

3568 = 3000+500+60+8

39610 = 30000+9000+600+10

Now multiply each value of 3568 with the values of 39610. Like:

3000 * 30000

3000 * 9000

3000 * 600

3000 * 8

and so on....

Step-by-step explanation:

5 0
3 years ago
Someone help me please and thank you!! ASAP :(
pantera1 [17]
<h3>Answer: Choice D) </h3>

Work Shown:

(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\

We must require that x \ne -12 and x \ne 3 to avoid having 0 in the denominator. This is why choice D is the answer.

3 0
3 years ago
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