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Aleks04 [339]
2 years ago
9

A vender sold a combined total of 131 sodas and hot dogs. The number of hot dogs sold was 31 less than the number of sodas sold.

Find the number of sodas sold and the number of hot dogs sold
Mathematics
1 answer:
puteri [66]2 years ago
5 0

Answer:

81 sodas and 50 hotdogs

Step-by-step explanation:

131 = x + x - 31

131 <em>+</em><em> </em><em>3</em><em>1</em><em> </em>= x + x - 31 <em>+</em><em> </em><em>3</em><em>1</em>

162 = x + x

x = 81

131 = 81 + (81 - 31)

131 = 81 sodas + 50 hot dogs

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Somebody please help me with this question!​
marta [7]

Answers:

P(A) = 7/12

P(B) = 1/2

=====================================================

Explanation:

To see how I calculated P(A), check out this link to this very similar question

brainly.com/question/27669586

--------------------

Now to calculate P(B)

If a number is divisible by 2, then the number is a multiple of 2.

In other words, the number is even.

Counting through the values in the table, you should find that there are 18 sums that are even (2, 4, 6, 8, 10 and 12). Refer to the dice chart below.

Here's a further breakdown

  • 1 copy of "2"
  • 3 copies of "4"
  • 5 copies of "6"
  • 5 copies of "8"
  • 3 copies of "10"
  • 1 copy of 12

Side note: We have nice symmetry going on.

There are 1+3+5+5+3+1 = 18 values total that are even numbers. The other half are odd numbers of course.

P(B) = 18/36 = (1*18)/(2*18) = 1/2

3 0
2 years ago
Andrew paid $10 for a burger. The burgers went in sale and there was a discount of 20%. What was the sale price of the burgers?
Viktor [21]
First you need to find the amount of money the discount decreased.
10(0.2)=2
Then, in order to find the sale price you need to subtract the discount price from the original price of the burger.
10-2=8
Answer: $8
6 0
3 years ago
Use the following function rule to find f(0).<br> f(x)=3(8)^x + 6<br> f(0)=
Anestetic [448]

Answer:

Answer: 9

Step-by-step explanation:

{ \tt{f(x) = 3( {8)}^{x} + 6 }}

• For f(0), substitute x with zero:

{ \tt{f(0) = 3( {8)}^{0}  + 6}} \\  \\ { \tt{f(0) = (3 \times 1) + 6}} \\  \\ { \tt{f(0) = 3 + 6}} \\  \\ { \boxed{ \tt{ \: f(0) = 9 \: }}}

6 0
2 years ago
Simplify the complex fraction.
lilavasa [31]

Given:

$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}

To find:

The simplified fraction.

Solution:

Step 1: Simplify the numerator

$\frac{(4 r)^{3}}{15 t^{4}}=\frac{4^3 r^{3}}{15 t^{4}}=\frac{64 r^{3}}{15 t^{4}}

Step 2: Simplify the denominator

$\frac{16 r}{(3 t)^{2}}=\frac{16 r}{3^2 t^{2}}= \frac{16 r}{9 t^{2}}

Step 3: Using step 1 and step 2

$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}} \right)}

Step 4: Using fraction rule:

$\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a \cdot d}{b \cdot c}

$\frac{\left(\frac{64 r^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{9 t^{2}}\right)}=\frac{64r^3 \cdot 9t^2}{16 r \cdot 15 t^4}

Cancel the common factor r and t², we get

           $=\frac{64 r^{2} \cdot 9 }{16  \cdot 15 t^2 }

Cancel the common factors 16 and 3 on both numerator and denominator.

           $=\frac{4 r^{2} \cdot 3 }{  5 t^2 }

           $=\frac{12 r^{2}  }{  5 t^2 }

$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}=\frac{12 r^{2}  }{  5 t^2 }

The simplified fraction is \frac{12 r^{2}  }{  5 t^2 }.

5 0
3 years ago
Suppose three players go on multiple rounds of kart race. In each round, every player has a winning probability of 1/3, independ
zepelin [54]

Answer:

a) 0.3246

b) 0.0043

Step-by-step explanation:

  • For player 1 ; Probability of winning = P(W) = 1/3
  • Probability of loosing; P(winning) + P( Loosing) = 1
  • P(L) = 1 - 1/3 = 2/3

a) To find Find P(N <= 10) = P(2)+P(3)+P(4)+P(5)+P(6)+P(7)+P(8)+P(9)+P(10)

= (1/3)^2 + (1/3)^2 x 2/3 + (1/3)^2 x (2/3)^2 + (1/3)^2x (2/3)^3 + (1/3)^2 x (2/3)^4

X (1/3)^2 x (2/3)^5 + (1/3)^2 x (2/3)^6 + (1/3)^2 x (2/3)^7 + (1/3)^2 x (2/3)^8

= 0.3246

b) Find P(N = 10) = (1/3)^2 x (2/3)^8 = 0.0043

7 0
3 years ago
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