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3 years ago

For the given equation, find the values of a, b, and c, determine the direction in which the parabola opens, and

Mathematics

1 answer:

skad [1K]3 years ago

6 0

Answer:

Table (C)

Step-by-step explanation:

Given equation of the parabola is,

f(x) = 9x² + 5x + 3

By comparing this equation with,

f(x) = ax² + bx + c

a = 9, b = 5 and c = 3

Since, leading coefficient (a) of the function is positive,

Parabola will open upwards.

For y-intercept,

Substitute x = 0 in the equation,

f(0) = 9(0)² + 5(0) + 3

f(0) = 3

Therefore, y-intercept is (0, 3).

Table (C) is the answer.

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4b+3=−9 i need help it is inportant

Fantom [35]

Answer:

b=-3

Step-by-step explanation:

4b+3=-9

-3 -3

subtract 3 from both sides like so. 3-3 cancels out. -9-3=-12.

4b=-12

youre left with 4b=12 so DIVIDE 4b by 4 and -12 by 4

4b/4=-12/4

4b divided by 4 is 1. -12 divided by 4 is -3

b=-3

plug -3 in for b to make sure its correct

4(-3)+3=-9

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4 years ago

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Slow and steady wins the race. The leather back sea turtle is the fastest known reptile, with a maximum speed of 21.9221.9221, p

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Step-by-step explanation:

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4 years ago

In a data distribution, the first quartile, the median and the means are 30.8, 48.5 and 42.0

kolbaska11 [484]

Answer:

$Q_3 = 56.45$ --- The third quartile

$Var = 370.18$ -- Variance

Step-by-step explanation:

Given

$Q_1 = 30.8$ -- First quartile

$Q_2 = 48.5$ --- Median

$\bar x = 42$ --- Mean

$Skp = -0.38$ --- Coefficient of skewness

Solving (9): The third quartile $Q_3$

This is calculated from

$Skp = \frac{Q_1 + Q_3 - 2Q_2}{Q_3 - Q_1}$

So, we have:

$-0.38 = \frac{30.8 + Q_3- 2*48.5}{Q_3 - 30.8}$

Cross Multiply

$-0.38 (Q_3 - 30.8)= 30.8 + Q_3- 2*48.5$

Open bracket

$-0.38Q_3 + 11.704= 30.8 + Q_3- 97.0$

Collect like terms

$-0.38Q_3 -Q_3= 30.8 - 97.0- 11.704$

$-1.38Q_3= -77.904$

Divide both sides -1.38

$Q_3 = \frac{-77.904}{-1.38}$

$Q_3 = 56.45$ --- approximated

Solving (b): The variance

First, calculate the standard deviation from:

$3IQR = 4SD$

$IQR= Q_3 - Q_1$

So:

$3IQR = 4SD$

$3(Q_3 - Q_1) = 4SD$

Make SD the subject

$SD = \frac{3}{4}(Q_3 - Q_1)$

$SD = \frac{3}{4}(56.45 - 30.8)$

$SD = \frac{3}{4}*25.65$

$SD = \frac{3*25.65}{4}$

$SD = \frac{76.95}{4}$

$SD = 19.24$

So, the variance is:

$Var = SD^2$

$Var = 19.24^2$

$Var = 370.18$

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3 years ago

In a card game, Alex has 2 diamonds 3 spades 4 clubs, and 1 heart. Without being able to see the cards wes is going to pick one

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Answer:

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Step-by-step explanation:

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