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Artist 52 [7]
3 years ago
5

A function f defined by f(x) = x² + px + q is such that f(3) = 6 and f¹(3) = 0. Find the value of q.

Mathematics
1 answer:
CaHeK987 [17]3 years ago
5 0

Answer:

q = 15

Step-by-step explanation:

Given

f(x) = x² + px + q , then

f(3) = 3² + 3p + q = 6 , that is

9 + 3p + q = 6 ( subtract 9 from both sides )

3p + q = - 3 → (1)

---------------------------------------

f'(x) = 2x + p , then

f'(3) = 2(3) + p = 0, that is

6 + p = 0 ( subtract 6 from both sides )

p = - 6

Substitute p = - 6 into (1)

3(- 6) + q = - 3

- 18 + q = - 3 ( add 18 to both sides )

q = 15

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vodomira [7]

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Step-by-step explanation:

We need to find factors of 42.

Factors: <em>Two numbers when multiplied if give you the required number then those 2 numbers are factors o that number.</em>

So, Factors of 42 are:

<em>1 x 42</em>

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So, All these numbers are factors of 42

Keywords: factors of numbers

Learn more about factors of numbers at:

  • brainly.com/question/1414350
  • brainly.com/question/1464739

#learnwithBrainly

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Step-by-step explanation:

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Pythagorean Theorem: a^2 + b^2 = c^2
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