1. 7 + -10 = -3.
2. -3 + -8 = -11
3. 4 + -5 = -1
4. 2 + -6 = -4
(You basically need to add negative numbers to positive numbers in order to get negative numbers.)
Answer: $31000 was loaned at 13%.
Step-by-step explanation:
Let x represent the amount loaned out at 13% interest rate.
Let y represent the amount loaned out at 5% interest rate.
The bank loaned out $68,000, part of it at the rate of 13% per year and the rest at a rate of 5%per year. It means that
x + y = 68000
The interest received made from $x in one year is
13/100 × x = 0.13x
The interest received made from $y in one year is
5/100 × x = 0.05y
If the interest received was $5880, it means that
0.13x + 0.05y = 5880- - - - - - - - - 1
Substituting x = 68000 - y into equation 1, it becomes
0.13(68000 - y) + 0.05y = 5880
8840 - 0.13y + 0.05y = 5880
- 0.13y + 0.05y = 5880 - 8840
- 0.08y = - 2960
y = - 2960/- 0.08
y = 37000
x = 68000 - y = 68000 - 37000
x = $31000
Answer:
Step-by-step explanation:
3*n*p*6 = 18np
Answer:
slope = 2
y intercept = ( 0 , -1 )
equation:
y = 2x - 1
Step-by-step explanation:
Annually The amount after 10 years = $ 7247.295
quarterly compound after 10 years = $7393.5
Continuously interest =$7,419
Given:
P = the principal amount
r = rate of interest
t = time in years
n = number of times the amount is compounding.
Principal = $4500
time= 10 year
Rate = 5%
To find: The amount after 10 years.
The principal amount is, P = $4500
The rate of interest is, r = 5% =5/100 = 0.05.
The time in years is, t = 10.
Using the quarterly compound interest formula:
A = P (1 + r / 4)4 t
A= 4500(1+.05/4)40
A= 4500(4.05/4)40
A= 4500(1.643)
Answer: The amount after 10 years = $7393.5
Using the Annually compound interest formula:
A = P (1 + r / 100) t
A= 4500(1+5/100)10
A= 4500(105/100)10
Answer: The amount after 10 years = $ 7247.295
Using the Continuously compound interest formula:
e stands for Napier’s number, which is approximately 2.7183

A= $2,919
Answer: The amount after 10 years = $4500+$2,919=$7,419
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