We need more info... but the domain is probably all real numbers
Answer:
the answer is right there x.8.90.^.34>^
Step-by-step explanation:
Jeff can run 2/3 of a mile per hour
Answer:
<u>y</u><u> </u><u>=</u><u> </u><u>1</u><u>4</u><u>/</u><u>3</u><u> </u><u>and</u><u> </u><u>2</u>
<u>x</u><u> </u><u>=</u><u> </u><u>-</u><u>1</u><u>3</u><u>/</u><u>3</u><u> </u><u>and</u><u> </u><u>1</u>
<u>(</u><u>-</u><u>1</u><u>3</u><u>/</u><u>3</u><u>,</u><u> </u><u>1</u><u>4</u><u>/</u><u>3</u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u>1</u><u>,</u><u> </u><u>2</u><u>)</u>
Step-by-step explanation:
<u>f</u><u>o</u><u>r</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>(</u><u>a</u><u>)</u>
make x the subject of the formular:
<u>f</u><u>o</u><u>r</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>(</u><u>b</u><u>)</u>
<u></u>
substitute for x as 5 - 2y in equation (b):
therefore,
substitute for all values of y in equation (c):
<u>f</u><u>o</u><u>r</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>1</u><u>4</u><u>/</u><u>3</u><u>:</u>
<u>f</u><u>o</u><u>r</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>2</u><u>:</u>