The answer should be this below
a- 4.16%
b- 7.5%
Answer:
21
Step-by-step explanation:
3:8
8x7 = 56
3x7 = 21
Calculate the mean, median, and mode of the following set of data. Round to the nearest tenth. 7, 3, 2, 1, 13, 8, 1, 5, 14, 11,
zysi [14]
Answer:
Mean = 7.3, median = 7, mode = 1.
Step-by-step explanation:
First arrange the data in order:
1 1 2 3 5 7 8 11 13 14 15
There are a total of 11 values.
Median = middle value = 7.
Mode = the most common number = 1.
Mean = sum / 11
= 80 / 11
= 7.3.
Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
Well as you can see 5 x 2/3= 3 1/3 there is 7 steps to figure it out
1. set up the problem
5 x 2/3
2. put a 1 on 5 to make it a fraction
5/1 x 2/3
3. multiply and divide
(5 x 2) / (1/3)
4. find out the answer
10/3
5. turn the answer into a mixed fraction
10 divided by 3= 3.1 3 stays the same you don't need to say 1
6. it equals
3 1/3
7. so the answer is
3 1/3