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pashok25 [27]
3 years ago
9

5(2x)=5/16 what would x be in this logarithmic equation?

Mathematics
1 answer:
Stolb23 [73]3 years ago
6 0

Answer:

The required value of x in the given logarithmic equation is -0.36

Step-by-step explanation:

The given logarithmic equation is :

5^{2x}=\frac{5}{16}

We need to find the required value of x in the given logarithmic equation.

5^{2x}=\frac{5}{16}\\\\\text{Taking log on both the sides}\\\\\log 5^{2x}=\log(\frac{5}{16})\\\\\implies 2x=\frac{\log 5-\log 16}{\log 5}\\\\\implies 2x=\frac{0.699-1.204}{0.699}\\\\\implies 2x = \frac{-0.505}{0.699}\\\\\implies 2x = -0.72\\\\\implies x = -0.36

Hence, the value of x in the given logarithmic equation is -0.36

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Step-by-step explanation:

Sn=n/2(2a+(n-1)d). n=20

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S20=10(10+57). d=8-5=3

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Hope this helps you

have a great day

3 0
3 years ago
Need help solving it. Quantitative Literacy.
ioda

1 lb ≈ 0.454 kg

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I'm not sure I understand the "do not" part of this question. What does it mean to convert from cubic inches (volume) to inches (length), and from centimeter to cubic centimeters?

In any case, you have

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… ≈ (0.454 kg)/(3.19 in)³ × ((1 in)/(2.54 cm))³

… ≈ (0.454 kg) × ((1 in)/((3.19 in) × (2.54 cm))³

… ≈ (0.454 kg) × (1/(8.10 cm))³

… ≈ (0.454 kg) × 1/(530.531 cm³)

… ≈ (0.454 kg)/(530.531 cm³)

… ≈ 0.000856 kg/cm³

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Read 2 more answers
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