9514 1404 393
Answer:
5 seconds
Step-by-step explanation:
Suppose the front parts of the trains meet at point A. Since both are the same length and traveling the same speed, each will pass point A in time ...
time = distance/speed
time = (1/18 mi)/(40 mi/h) = (1/720 h) × (3600 s)/(1 h) = 5 s
That is, the rear part of each train will be at point A 5 seconds after the front part.
The rear parts will pass each other 5 seconds after the front parts meet.
Answer:
351 adults and 275 students
Step-by-step explanation:
We can set-up a system of equations to find the number of adults. We know students and adults attended. We will let s be the number of students and a be the number of adults. Since 626 tickets were purchased, then s+a=626.
We also know that 74 fewer student tickets then adult tickets. So s+76=a, the number of student tickets plus 76 will be the number of adult tickets.
We will solve by substituting one equation into the other. We substitute a=76+s into s+a=626. Simplify and isolate the variable a.
s+a=626
s+76+s=626
2s+76=626
2s+76-76=626-76
2s=550
s=275
This means that 275 students attended and 351 adults attended since 275+351=626.
5/6÷2/1
=5/6×1/2
=5/12 i hope this helps
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Answer:
4680 I think
Step-by-step explanation:
I divided your loan and interest rate by 5%
