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NeTakaya
2 years ago
6

If Quick copy recently charged 49 cents per page for color copies and 9 cents per page for back and white copies. If Shirlees bi

ll for 90 copies is $12.90, how many copies of each type were made? It needs to be written like in algebra let x= or x+y something like that thanks
Mathematics
1 answer:
raketka [301]2 years ago
6 0
Is that the full question or does it say like a certain percent of $12.90 was color or?
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PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEE HELP ME. IF I PASS THIS I GET TO GO TO DISNEY WORLD.
Vera_Pavlovna [14]

Answer:

I think it would be C

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Latesha buys some tennis balls at $1 each and rackets at $12 each for her PE class. She buys twice as many balls as rackets. She
marysya [2.9K]
I would go with A it makes most sense to me .
3 0
3 years ago
Evaluate 150 + 3p for p = 30
LiRa [457]

150+3p

p=30

150+3(30)

150+90

240

When p=30 in 150+3p, the final value is 240.

7 0
3 years ago
Read 2 more answers
How many natural numbers N have the property among 1,2,..........,N exactly 30% are divisible by 3?
k0ka [10]

Answer:

The answer is B. 2.

Step-by-step explanation:

We know that for N = 1 and N = 2, none of them are divisible by 3.

For N = 3, 33.33% are divisible by 3.  For N = 4, 25% (which is already less than 30%), so N = 5 would also be less.

At N = 6, we're back up to 33.33%.  N = 7 is already less than 30%.

At N = 9, you guessed it, 33.33%.  N = 10 is 30% (3, 6, and 9).  So we have one case.

Moving along, at N = 18, 33.33%.  N = 20 is again 30% (3, 6, 9, 12, 15, and 18).  Two cases now.

Finally, at N = 21, again 33.33%.  N = 22 and N = 23 are both greater than 30%.  As we continue this, for any N after 20, we will always be greater than 30%.

4 0
3 years ago
Evaluate triple integral ∫ ∫ ∫ 8xydV, where E lies under the plane z = 1+x+y and above the E region in the xy-plane bounded by t
vazorg [7]

Answer:

\mathbf{=\dfrac{163.384}{15}}

Step-by-step explanation:

\int \int \limits_{E} \int \ 8 xy dV = \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} \int\limits^{1+x+y}_{0} \ 8xy dz dydx

= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} [ 8xyz]^{z=1+x+y}_{z=0}  \   \ dy dx

= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} 8xy (1+x+y) dy dx

= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} 8xy+8x^2y+8xy^2 \ \ dy dx

= \int\limits^{1}_{0}  \ [ 4xy^2+4x^2y^2+2.7xy^3]^{ y= \sqrt{x}}_{y-0} \ \  dx

= \int\limits^{1}_{0} \   4x (\sqrt{x})^2+4x^2(\sqrt{x})^2+2.7x(\sqrt{x})^3\ \  dx

= \int\limits^{1}_{0} \   4x^2+4x^3+2.7x^{5/2} \  dx

\mathbf{=\dfrac{163.384}{15}}

7 0
3 years ago
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