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marin [14]
3 years ago
13

I need hellpp i need to know what the angle is and what x is​

Mathematics
2 answers:
mestny [16]3 years ago
4 0

Answer:

x = 7

Step-by-step explanation:

The 2 marked angles are Alternate exterior angles ( they are outside the parallel lines ) and are congruent, that is

10x = 9x + 7 ( subtract 9x from both sides )

x = 7

valentina_108 [34]3 years ago
4 0

Answer:

x = 7.

Angle = 70 degrees.

Step-by-step explanation:

These 2 angles are exterior alternate angles and so they are equal.

So  9x + 7 = 10x

Subtract 7 from both sides:

9x + 7 - 7 = 10x - 7

9x = 10x - 7

Subtract 10x from both sides:

9x - 10x = 10x -10x - 7

-x = -7

x = 7

The measure of the angle = 10x

= 10*7

= 70 degrees.

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What is the first quartile of the following data set?<br> 15, 18, 20, 21, 23, 24, 26, 29, 34, 37, 40
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20.5

Step-by-step explanation:

20 + 21 = 41.   Divide 41 by 2 than you get 20.5.

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Simplify: |3 – 10| – (12 / 4 + 2)^2<br> 0 - 32<br> O – 18<br> O3<br> 0 - 6
MakcuM [25]

Answer:

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Step-by-step explanation:

Simplify: |3 – 10| – (12 / 4 + 2)^2

|3 - 10| - (\frac{12}{4}  + 2)^2\\\\|-7|-(\frac{12}{4}  + 2)^2 < == absolute\ numbers\ are\ always\ positive\\\\7-(3+2)^2 < ==add\ numbers\ in\ parenthesis\\\\7-5^2 < ==square\ the\ number\ (5)\\\\7-25 < ==add\ numbers\\\\-18 < ==final\ answer

Hope this helps!

6 0
2 years ago
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a game is played by drawing 4 cards from a standard playing deck and replacing each card after it is drawn. find the probability
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It is a 1 in 13 chance of drawing at least 1 ace. 
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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x
Andrei [34K]

Answer:

\large\boxed{A.\ (x+6)^2+(y+10)^2=20}

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

Substitute:

x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute (-6, -10) and (-8, -6):

r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}

Finally we have

(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20

5 0
3 years ago
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